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SQL26. 计算25岁以上和以下的用户数量

描述

题目:现在运营想要将用户划分为25岁以下和25岁及以上两个年龄段,分别查看这两个年龄段用户数量
本题注意:age为null 也记为 25岁以下

示例:user_profile
id device_id gender age university gpa active_days_within_30
question_cnt
answer_cnt
1 2138 male 21 北京大学 3.4 7 2 12
2 3214 male 复旦大学 4 15 5 25
3 6543 female 20 北京大学 3.2 12 3 30
4 2315 female 23 浙江大学 3.6 5 1 2
5 5432 male 25 山东大学 3.8 20 15 70
6 2131 male 28 山东大学 3.3 15 7 13
7 4321 male 26 复旦大学 3.6 9 6 52

根据示例,你的查询应返回以下结果:
age_cut number
25岁以下 4
25岁及以上
3

示例1

输入:

drop table if exists `user_profile`;
drop table if  exists `question_practice_detail`;
CREATE TABLE `user_profile` (
`id` int NOT NULL,
`device_id` int NOT NULL,
`gender` varchar(14) NOT NULL,
`age` int ,
`university` varchar(32) NOT NULL,
`gpa` float,
`active_days_within_30` int ,
`question_cnt` int ,
`answer_cnt` int 
);
CREATE TABLE `question_practice_detail` (
`id` int NOT NULL,
`device_id` int NOT NULL,
`question_id`int NOT NULL,
`result` varchar(32) NOT NULL
);
CREATE TABLE `question_detail` (
`id` int NOT NULL,
`question_id`int NOT NULL,
`difficult_level` varchar(32) NOT NULL
);

INSERT INTO user_profile VALUES(1,2138,'male',21,'北京大学',3.4,7,2,12);
INSERT INTO user_profile VALUES(2,3214,'male',null,'复旦大学',4.0,15,5,25);
INSERT INTO user_profile VALUES(3,6543,'female',20,'北京大学',3.2,12,3,30);
INSERT INTO user_profile VALUES(4,2315,'female',23,'浙江大学',3.6,5,1,2);
INSERT INTO user_profile VALUES(5,5432,'male',25,'山东大学',3.8,20,15,70);
INSERT INTO user_profile VALUES(6,2131,'male',28,'山东大学',3.3,15,7,13);
INSERT INTO user_profile VALUES(7,4321,'male',28,'复旦大学',3.6,9,6,52);
INSERT INTO question_practice_detail VALUES(1,2138,111,'wrong');
INSERT INTO question_practice_detail VALUES(2,3214,112,'wrong');
INSERT INTO question_practice_detail VALUES(3,3214,113,'wrong');
INSERT INTO question_practice_detail VALUES(4,6543,111,'right');
INSERT INTO question_practice_detail VALUES(5,2315,115,'right');
INSERT INTO question_practice_detail VALUES(6,2315,116,'right');
INSERT INTO question_practice_detail VALUES(7,2315,117,'wrong');
INSERT INTO question_practice_detail VALUES(8,5432,117,'wrong');
INSERT INTO question_practice_detail VALUES(9,5432,112,'wrong');
INSERT INTO question_practice_detail VALUES(10,2131,113,'right');
INSERT INTO question_practice_detail VALUES(11,5432,113,'wrong');
INSERT INTO question_practice_detail VALUES(12,2315,115,'right');
INSERT INTO question_practice_detail VALUES(13,2315,116,'right');
INSERT INTO question_practice_detail VALUES(14,2315,117,'wrong');
INSERT INTO question_practice_detail VALUES(15,5432,117,'wrong');
INSERT INTO question_practice_detail VALUES(16,5432,112,'wrong');
INSERT INTO question_practice_detail VALUES(17,2131,113,'right');
INSERT INTO question_practice_detail VALUES(18,5432,113,'wrong');
INSERT INTO question_practice_detail VALUES(19,2315,117,'wrong');
INSERT INTO question_practice_detail VALUES(20,5432,117,'wrong');
INSERT INTO question_practice_detail VALUES(21,5432,112,'wrong');
INSERT INTO question_practice_detail VALUES(22,2131,113,'right');
INSERT INTO question_practice_detail VALUES(23,5432,113,'wrong');
INSERT INTO question_detail VALUES(1,111,'hard');
INSERT INTO question_detail VALUES(2,112,'medium');
INSERT INTO question_detail VALUES(3,113,'easy');
INSERT INTO question_detail VALUES(4,115,'easy');
INSERT INTO question_detail VALUES(5,116,'medium');
INSERT INTO question_detail VALUES(6,117,'easy');

输出:

25岁以下|4
25岁及以上|3

原站题解

上次编辑到这里,代码来自缓存 点击恢复默认模板

Mysql 解法, 执行用时: 36ms, 内存消耗: 6392KB, 提交时间: 2021-12-08

SELECT if(age>=25,'25岁及以上','25岁以下') as age_cut,count(device_id) as number
from user_profile
group by age_cut

Mysql 解法, 执行用时: 36ms, 内存消耗: 6440KB, 提交时间: 2022-01-25

SELECT case 
                     when age<25 or age is null then  '25岁以下'
                     when age>=25 then '25岁及以上'
       end age_cut,count(*) number
FROM user_profile
group by age_cut

Mysql 解法, 执行用时: 36ms, 内存消耗: 6484KB, 提交时间: 2022-01-25

select
case when age<25 or age is null then "25岁以下"
     when age>=25 then "25岁及以上"
     end as age_cut, count(*)  number
from user_profile
group by age_cut;

Mysql 解法, 执行用时: 36ms, 内存消耗: 6612KB, 提交时间: 2021-12-27

SELECT 
case
when age>=25 then '25岁及以上' else '25岁以下' end age_cut
,COUNT(device_id) number 
from user_profile
group by age_cut

Mysql 解法, 执行用时: 37ms, 内存消耗: 6384KB, 提交时间: 2022-01-01

select '25岁以下' as age_cut, count(1) as number from user_profile where age < 25 or age is null
union 
select '25岁及以上' as age_cut, count(1) as number from user_profile where age>= 25