SQL26. 计算25岁以上和以下的用户数量
描述
id | device_id | gender | age | university | gpa | active_days_within_30 | question_cnt | answer_cnt |
1 | 2138 | male | 21 | 北京大学 | 3.4 | 7 | 2 | 12 |
2 | 3214 | male | 复旦大学 | 4 | 15 | 5 | 25 | |
3 | 6543 | female | 20 | 北京大学 | 3.2 | 12 | 3 | 30 |
4 | 2315 | female | 23 | 浙江大学 | 3.6 | 5 | 1 | 2 |
5 | 5432 | male | 25 | 山东大学 | 3.8 | 20 | 15 | 70 |
6 | 2131 | male | 28 | 山东大学 | 3.3 | 15 | 7 | 13 |
7 | 4321 | male | 26 | 复旦大学 | 3.6 | 9 | 6 | 52 |
age_cut | number |
25岁以下 | 4 |
25岁及以上 | 3 |
示例1
输入:
drop table if exists `user_profile`; drop table if exists `question_practice_detail`; CREATE TABLE `user_profile` ( `id` int NOT NULL, `device_id` int NOT NULL, `gender` varchar(14) NOT NULL, `age` int , `university` varchar(32) NOT NULL, `gpa` float, `active_days_within_30` int , `question_cnt` int , `answer_cnt` int ); CREATE TABLE `question_practice_detail` ( `id` int NOT NULL, `device_id` int NOT NULL, `question_id`int NOT NULL, `result` varchar(32) NOT NULL ); CREATE TABLE `question_detail` ( `id` int NOT NULL, `question_id`int NOT NULL, `difficult_level` varchar(32) NOT NULL ); INSERT INTO user_profile VALUES(1,2138,'male',21,'北京大学',3.4,7,2,12); INSERT INTO user_profile VALUES(2,3214,'male',null,'复旦大学',4.0,15,5,25); INSERT INTO user_profile VALUES(3,6543,'female',20,'北京大学',3.2,12,3,30); INSERT INTO user_profile VALUES(4,2315,'female',23,'浙江大学',3.6,5,1,2); INSERT INTO user_profile VALUES(5,5432,'male',25,'山东大学',3.8,20,15,70); INSERT INTO user_profile VALUES(6,2131,'male',28,'山东大学',3.3,15,7,13); INSERT INTO user_profile VALUES(7,4321,'male',28,'复旦大学',3.6,9,6,52); INSERT INTO question_practice_detail VALUES(1,2138,111,'wrong'); INSERT INTO question_practice_detail VALUES(2,3214,112,'wrong'); INSERT INTO question_practice_detail VALUES(3,3214,113,'wrong'); INSERT INTO question_practice_detail VALUES(4,6543,111,'right'); INSERT INTO question_practice_detail VALUES(5,2315,115,'right'); INSERT INTO question_practice_detail VALUES(6,2315,116,'right'); INSERT INTO question_practice_detail VALUES(7,2315,117,'wrong'); INSERT INTO question_practice_detail VALUES(8,5432,117,'wrong'); INSERT INTO question_practice_detail VALUES(9,5432,112,'wrong'); INSERT INTO question_practice_detail VALUES(10,2131,113,'right'); INSERT INTO question_practice_detail VALUES(11,5432,113,'wrong'); INSERT INTO question_practice_detail VALUES(12,2315,115,'right'); INSERT INTO question_practice_detail VALUES(13,2315,116,'right'); INSERT INTO question_practice_detail VALUES(14,2315,117,'wrong'); INSERT INTO question_practice_detail VALUES(15,5432,117,'wrong'); INSERT INTO question_practice_detail VALUES(16,5432,112,'wrong'); INSERT INTO question_practice_detail VALUES(17,2131,113,'right'); INSERT INTO question_practice_detail VALUES(18,5432,113,'wrong'); INSERT INTO question_practice_detail VALUES(19,2315,117,'wrong'); INSERT INTO question_practice_detail VALUES(20,5432,117,'wrong'); INSERT INTO question_practice_detail VALUES(21,5432,112,'wrong'); INSERT INTO question_practice_detail VALUES(22,2131,113,'right'); INSERT INTO question_practice_detail VALUES(23,5432,113,'wrong'); INSERT INTO question_detail VALUES(1,111,'hard'); INSERT INTO question_detail VALUES(2,112,'medium'); INSERT INTO question_detail VALUES(3,113,'easy'); INSERT INTO question_detail VALUES(4,115,'easy'); INSERT INTO question_detail VALUES(5,116,'medium'); INSERT INTO question_detail VALUES(6,117,'easy');
输出:
25岁以下|4 25岁及以上|3
Mysql 解法, 执行用时: 36ms, 内存消耗: 6392KB, 提交时间: 2021-12-08
SELECT if(age>=25,'25岁及以上','25岁以下') as age_cut,count(device_id) as number from user_profile group by age_cut
Mysql 解法, 执行用时: 36ms, 内存消耗: 6440KB, 提交时间: 2022-01-25
SELECT case when age<25 or age is null then '25岁以下' when age>=25 then '25岁及以上' end age_cut,count(*) number FROM user_profile group by age_cut
Mysql 解法, 执行用时: 36ms, 内存消耗: 6484KB, 提交时间: 2022-01-25
select case when age<25 or age is null then "25岁以下" when age>=25 then "25岁及以上" end as age_cut, count(*) number from user_profile group by age_cut;
Mysql 解法, 执行用时: 36ms, 内存消耗: 6612KB, 提交时间: 2021-12-27
SELECT case when age>=25 then '25岁及以上' else '25岁以下' end age_cut ,COUNT(device_id) number from user_profile group by age_cut
Mysql 解法, 执行用时: 37ms, 内存消耗: 6384KB, 提交时间: 2022-01-01
select '25岁以下' as age_cut, count(1) as number from user_profile where age < 25 or age is null union select '25岁及以上' as age_cut, count(1) as number from user_profile where age>= 25