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SQL27. 查看不同年龄段的用户明细

描述

题目:现在运营想要将用户划分为20岁以下,20-24岁,25岁及以上三个年龄段,分别查看不同年龄段用户的明细情况,请取出相应数据。(注:年龄为空请返回其他



示例:user_profile
id device_id gender age university gpa active_days_within_30
question_cnt
answer_cnt
1 2138 male 21 北京大学 3.4 7 2 12
2 3214 male 复旦大学 4 15 5 25
3 6543 female 20 北京大学 3.2 12 3 30
4 2315 female 23 浙江大学 3.6 5 1 2
5 5432 male 25 山东大学 3.8 20 15 70
6 2131 male 28 山东大学 3.3 15 7 13
7 4321 male 26 复旦大学 3.6 9 6 52

根据示例,你的查询应返回以下结果:
device_id gender age_cut
2138 male 20-24岁
3214
male 其他
6543 female 20-24岁
2315
female 20-24岁
5432
male
25岁及以上
2131
male
25岁及以上
4321 male
25岁及以上

示例1

输入:

drop table if exists `user_profile`;
drop table if  exists `question_practice_detail`;
CREATE TABLE `user_profile` (
`id` int NOT NULL,
`device_id` int NOT NULL,
`gender` varchar(14) NOT NULL,
`age` int ,
`university` varchar(32) NOT NULL,
`gpa` float,
`active_days_within_30` int ,
`question_cnt` int ,
`answer_cnt` int 
);
CREATE TABLE `question_practice_detail` (
`id` int NOT NULL,
`device_id` int NOT NULL,
`question_id`int NOT NULL,
`result` varchar(32) NOT NULL
);
CREATE TABLE `question_detail` (
`id` int NOT NULL,
`question_id`int NOT NULL,
`difficult_level` varchar(32) NOT NULL
);

INSERT INTO user_profile VALUES(1,2138,'male',21,'北京大学',3.4,7,2,12);
INSERT INTO user_profile VALUES(2,3214,'male',null,'复旦大学',4.0,15,5,25);
INSERT INTO user_profile VALUES(3,6543,'female',20,'北京大学',3.2,12,3,30);
INSERT INTO user_profile VALUES(4,2315,'female',23,'浙江大学',3.6,5,1,2);
INSERT INTO user_profile VALUES(5,5432,'male',25,'山东大学',3.8,20,15,70);
INSERT INTO user_profile VALUES(6,2131,'male',28,'山东大学',3.3,15,7,13);
INSERT INTO user_profile VALUES(7,4321,'male',28,'复旦大学',3.6,9,6,52);
INSERT INTO question_practice_detail VALUES(1,2138,111,'wrong');
INSERT INTO question_practice_detail VALUES(2,3214,112,'wrong');
INSERT INTO question_practice_detail VALUES(3,3214,113,'wrong');
INSERT INTO question_practice_detail VALUES(4,6543,111,'right');
INSERT INTO question_practice_detail VALUES(5,2315,115,'right');
INSERT INTO question_practice_detail VALUES(6,2315,116,'right');
INSERT INTO question_practice_detail VALUES(7,2315,117,'wrong');
INSERT INTO question_practice_detail VALUES(8,5432,117,'wrong');
INSERT INTO question_practice_detail VALUES(9,5432,112,'wrong');
INSERT INTO question_practice_detail VALUES(10,2131,113,'right');
INSERT INTO question_practice_detail VALUES(11,5432,113,'wrong');
INSERT INTO question_practice_detail VALUES(12,2315,115,'right');
INSERT INTO question_practice_detail VALUES(13,2315,116,'right');
INSERT INTO question_practice_detail VALUES(14,2315,117,'wrong');
INSERT INTO question_practice_detail VALUES(15,5432,117,'wrong');
INSERT INTO question_practice_detail VALUES(16,5432,112,'wrong');
INSERT INTO question_practice_detail VALUES(17,2131,113,'right');
INSERT INTO question_practice_detail VALUES(18,5432,113,'wrong');
INSERT INTO question_practice_detail VALUES(19,2315,117,'wrong');
INSERT INTO question_practice_detail VALUES(20,5432,117,'wrong');
INSERT INTO question_practice_detail VALUES(21,5432,112,'wrong');
INSERT INTO question_practice_detail VALUES(22,2131,113,'right');
INSERT INTO question_practice_detail VALUES(23,5432,113,'wrong');
INSERT INTO question_detail VALUES(1,111,'hard');
INSERT INTO question_detail VALUES(2,112,'medium');
INSERT INTO question_detail VALUES(3,113,'easy');
INSERT INTO question_detail VALUES(4,115,'easy');
INSERT INTO question_detail VALUES(5,116,'medium');
INSERT INTO question_detail VALUES(6,117,'easy');

输出:

2138|male|20-24岁
3214|male|其他
6543|female|20-24岁
2315|female|20-24岁
5432|male|25岁及以上
2131|male|25岁及以上
4321|male|25岁及以上

原站题解

上次编辑到这里,代码来自缓存 点击恢复默认模板

Mysql 解法, 执行用时: 36ms, 内存消耗: 6448KB, 提交时间: 2022-01-23

select device_id,gender,case when age<20 then '20岁以下'
when age>=20 and age<=24 then '20-24岁'
when age>=25 then '25岁及以上'
when age is null then '其他'
end as age_cut
from user_profile

Mysql 解法, 执行用时: 36ms, 内存消耗: 6456KB, 提交时间: 2021-12-14

select device_id,gender,
case 
when age<20 then '20岁以下'
when age <=24 and age>=20 then '20-24岁'
when age>=25 then '25岁及以上'
else '其他'
end as age_cut
from user_profile

Mysql 解法, 执行用时: 36ms, 内存消耗: 6500KB, 提交时间: 2021-12-08

select device_id,
       gender,
       case
        when age >= 25 then '25岁及以上'
        when age < 20 then '20岁以下'
        when 20 <= age < 25 then '20-24岁'
        else '其他' 
       end as age_cut
from user_profile

Mysql 解法, 执行用时: 36ms, 内存消耗: 6516KB, 提交时间: 2022-01-25

select device_id,gender,(case
  when age >= 20 and age <= 24 then '20-24岁'
  when age < 20 then '20岁以下'
  when age >= 25 then '25岁及以上'
  else '其他' end ) as age_cut
  from user_profile
  
  

Mysql 解法, 执行用时: 37ms, 内存消耗: 6384KB, 提交时间: 2022-01-22

# select device_id , gender , (case when age >= 20 and age <= 24 then '20-24岁' 
#         when age >= 25 then '25岁及以上' 
#         else '其他' end) age_cnt
# from user_profile


select device_id , gender , if( age >= 20 and age <= 24 , '20-24岁' ,
        if( age >= 25 , '25岁及以上' ,'其他' )) age_cnt
from user_profile