SQL206. 获取每个部门中当前员工薪水最高的相关信息
描述
emp_no | dept_no | from_date | to_date |
10001 | d001 | 1986-06-26 | 9999-01-01 |
10002 | d001 | 1996-08-03 | 9999-01-01 |
10003 | d002 | 1996-08-03 | 9999-01-01 |
emp_no | salary | from_date | to_date |
10001 | 88958 | 2002-06-22 | 9999-01-01 |
10002 | 72527 | 2001-08-02 | 9999-01-01 |
10003 | 92527 | 2001-08-02 | 9999-01-01 |
dept_no | emp_no | maxSalary |
d001 | 10001 | 88958 |
d002 | 10003 | 92527 |
示例1
输入:
drop table if exists `dept_emp` ; drop table if exists `salaries` ; CREATE TABLE `dept_emp` ( `emp_no` int(11) NOT NULL, `dept_no` char(4) NOT NULL, `from_date` date NOT NULL, `to_date` date NOT NULL, PRIMARY KEY (`emp_no`,`dept_no`)); CREATE TABLE `salaries` ( `emp_no` int(11) NOT NULL, `salary` int(11) NOT NULL, `from_date` date NOT NULL, `to_date` date NOT NULL, PRIMARY KEY (`emp_no`,`from_date`)); INSERT INTO dept_emp VALUES(10001,'d001','1986-06-26','9999-01-01'); INSERT INTO dept_emp VALUES(10002,'d001','1996-08-03','9999-01-01'); INSERT INTO dept_emp VALUES(10003,'d002','1996-08-03','9999-01-01'); INSERT INTO salaries VALUES(10001,88958,'2002-06-22','9999-01-01'); INSERT INTO salaries VALUES(10002,72527,'2001-08-02','9999-01-01'); INSERT INTO salaries VALUES(10003,92527,'2001-08-02','9999-01-01');
输出:
d001|10001|88958 d002|10003|92527
Sqlite 解法, 执行用时: 10ms, 内存消耗: 3256KB, 提交时间: 2021-07-29
select dept_no,d.emp_no,max(s.salary) from dept_emp d join salaries s on d.emp_no = s.emp_no group by d.dept_no
Sqlite 解法, 执行用时: 10ms, 内存消耗: 3264KB, 提交时间: 2021-07-25
select d.dept_no,d.emp_no,max(s.salary) as maxSalary from dept_emp d inner join salaries s on d.emp_no = s.emp_no group by d.dept_no
Sqlite 解法, 执行用时: 10ms, 内存消耗: 3328KB, 提交时间: 2021-07-24
select dept_no,a.emp_no,max(salary) as maxSalary from dept_emp as a left join salaries as b on a.emp_no=b.emp_no group by dept_no
Sqlite 解法, 执行用时: 10ms, 内存消耗: 3340KB, 提交时间: 2021-08-04
select a.dept_no,a.emp_no,b.salary from dept_emp as a left join salaries as b on a.emp_no = b.emp_no group by dept_no having b.salary = max(b.salary) order by dept_no
Sqlite 解法, 执行用时: 10ms, 内存消耗: 3352KB, 提交时间: 2021-08-27
select e.dept_no,e.emp_no,Max(s.salary) as maxsalary from dept_emp as e join salaries as s on e.emp_no = s.emp_no GROUP by dept_no order by dept_no