查找employees表emp_no与last

emp_no	birth_date	first_name	last_name	gender	hire_date
10001	1953-09-02	Georgi	Facello	M	1986-06-26
10002	1964-06-02	Bezalel	Simmel	F	1985-11-21
10003	1959-12-03	Bezalel	Mary	M	1986-08-28
10004	1954-05-01	Christian	Koblick	M	1986-12-01
10005	1953-11-07	Mary	Sluis	F	1990-01-22

请你查找employees表所有emp_no为奇数，且last_name不为Mary的员工信息，并按照hire_date逆序排列，以上例子查询结果如下:

emp_no	birth_date	first_name	last_name	gender	hire_date
10005	1953-11-07	Mary	Sluis	F	1990-01-22
10001	1953-09-02	Georgi	Facello	M	1986-06-26

示例1

输入:

drop table if exists  `employees` ; 
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
INSERT INTO employees VALUES(10001,'1953-09-02','Georgi','Facello','M','1986-06-26');
INSERT INTO employees VALUES(10002,'1964-06-02','Bezalel','Simmel','F','1985-11-21');
INSERT INTO employees VALUES(10003,'1959-12-03','Bezalel','Mary','M','1986-08-28');
INSERT INTO employees VALUES(10004,'1954-05-01','Chirstian','Koblick','M','1986-12-01');
INSERT INTO employees VALUES(10005,'1953-11-07','Mary','Sluis','F','1990-01-22');

输出:

10005|1953-11-07|Mary|Sluis|F|1990-01-22
10001|1953-09-02|Georgi|Facello|M|1986-06-26

原站题解

上次编辑到这里，代码来自缓存点击恢复默认模板

Sqlite 解法, 执行用时: 9ms, 内存消耗: 3372KB, 提交时间: 2021-08-09

select * 
from employees
where emp_no % 2 = 1 and last_name <> 'Mary'
order by hire_date desc

Sqlite 解法, 执行用时: 9ms, 内存消耗: 3380KB, 提交时间: 2021-08-09


select * from employees where emp_no % 2 == 1 and last_name != 'Mary'
order by hire_date desc

Sqlite 解法, 执行用时: 9ms, 内存消耗: 3408KB, 提交时间: 2021-08-09

select *from employees
where emp_no % 2=1
and last_name !='Mary'
order by hire_date desc

Sqlite 解法, 执行用时: 10ms, 内存消耗: 3168KB, 提交时间: 2020-12-24

select *
from employees
where emp_no%2=1 and last_name !='Mary'
order by hire_date desc

Sqlite 解法, 执行用时: 10ms, 内存消耗: 3172KB, 提交时间: 2020-10-29

select *
from employees 
where emp_no%2=1
order by hire_date desc

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