CPP44. 子类中调用父类构造
描述
有父类 Base，内部定义了 x、y 属性。有子类 Sub，继承自父类 Base。子类新增了一个 z 属性，并且定义了 calculate 方法，在此方法内计算了父类和子类中 x、y、z 属性三者的乘积。请补全子类构造方法的初始化逻辑，使得该计算逻辑能够正确执行。输入描述
三个整数：x, y, z输出描述
三个整数的乘积：x*y*z示例1
输入:
1 2 3
输出:
6
C++ 解法, 执行用时: 2ms, 内存消耗: 392KB, 提交时间: 2021-11-19
#include <iostream>
using namespace std;
class Base {
private:
int x;
int y;
public:
Base(int x, int y) {
this->x = x;
this->y = y;
}
Base() {
}
int getX() {
return x;
}
int getY() {
return y;
}
};
class Sub : public Base {
private:
int z;
public:
Sub(int x, int y, int z) : Base(x,y){
// write your code here
this->z = z;
}
int getZ() {
return z;
}
int calculate() {
return Base::getX() * Base::getY() * this->getZ();
}
};
int main() {
int x, y, z;
cin >> x;
cin >> y;
cin >> z;
Sub sub(x, y, z);
cout << sub.calculate() << endl;
return 0;
}
C++ 解法, 执行用时: 2ms, 内存消耗: 396KB, 提交时间: 2021-11-28
#include <iostream>
using namespace std;
class Base {
private:
int x;
int y;
public:
Base(int x, int y) {
this->x = x;
this->y = y;
}
int getX() {
return x;
}
int getY() {
return y;
}
};
class Sub : public Base {
private:
int z;
public:
Sub(int x, int y, int z):Base(x,y) {
// write your code here
this->z=z;
}
int getZ() {
return z;
}
int calculate() {
return Base::getX() * Base::getY() * this->getZ();
}
};
int main() {
int x, y, z;
cin >> x;
cin >> y;
cin >> z;
Sub sub(x, y, z);
cout << sub.calculate() << endl;
return 0;
}
C++ 解法, 执行用时: 2ms, 内存消耗: 396KB, 提交时间: 2021-11-19
#include <iostream>
using namespace std;
class Base {
private:
int x;
int y;
public:
Base(int x, int y) {
this->x = x;
this->y = y;
}
int getX() {
return x;
}
int getY() {
return y;
}
};
class Sub : public Base {
private:
int z;
public:
Sub(int x, int y, int z) : Base(x,y) {
// write your code here
this-> z = z;
}
int getZ() {
return z;
}
int calculate() {
return Base::getX() * Base::getY() * this->getZ();
}
};
int main() {
int x, y, z;
cin >> x;
cin >> y;
cin >> z;
Sub sub(x, y, z);
cout << sub.calculate() << endl;
return 0;
}
C++ 解法, 执行用时: 2ms, 内存消耗: 400KB, 提交时间: 2021-11-25
#include <iostream>
using namespace std;
class Base {
private:
int x;
int y;
public:
Base(int x, int y) {
this->x = x;
this->y = y;
}
int getX() {
return x;
}
int getY() {
return y;
}
};
class Sub : public Base {
private:
int z;
public:
Sub(int x, int y, int z) :Base(x,y)
{
// write your code here
this->z=z;
}
int getZ() {
return z;
}
int calculate() {
return Base::getX() * Base::getY() * this->getZ();
}
};
int main() {
int x, y, z;
cin >> x;
cin >> y;
cin >> z;
Sub sub(x, y, z);
cout << sub.calculate() << endl;
return 0;
}
C++ 解法, 执行用时: 2ms, 内存消耗: 404KB, 提交时间: 2022-01-25
#include <iostream>
using namespace std;
class Base {
private:
int x;
int y;
public:
Base(int x, int y) {
this->x = x;
this->y = y;
}
int getX() {
return x;
}
int getY() {
return y;
}
};
class Sub : public Base {
private:
int z;
public:
Sub(int x, int y, int z) : Base(x,y) {
// write your code here
this->z=z;
}
int getZ() {
return z;
}
int calculate() {
return Base::getX() * Base::getY() * this->getZ();
}
};
int main() {
int x, y, z;
cin >> x;
cin >> y;
cin >> z;
Sub sub(x, y, z);
cout << sub.calculate() << endl;
return 0;
}