CPP45. 重写子类计算逻辑
描述
在父类 Base 中定义了计算方法 calculate()，该方法用于计算两个数的乘积（X*Y）。请在子类 Sub 中重写该方法，将计算逻辑由乘法改为除法（X/Y）。注意，当分母为0时输出“Error”。输入描述
两个整数输出描述
两个整数的商(int类型，不考虑小数部分)示例1
输入:
6 2
输出:
3
C++ 解法, 执行用时: 2ms, 内存消耗: 396KB, 提交时间: 2021-10-31
#include <iostream>
using namespace std;
class Base {
private:
int x;
int y;
public:
Base(int x, int y) {
this->x = x;
this->y = y;
}
int getX() {
return x;
}
int getY() {
return y;
}
void calculate() {
cout << getX() * getY() << endl;
}
};
class Sub : public Base {
// write your code here......
public:
Sub(int x, int y) : Base(x, y) {}
void calculate() {
if( getY() ) cout << getX()/getY() << endl;
else cout << "Error" << endl;
}
};
int main() {
int x, y, z;
cin >> x;
cin >> y;
Sub sub(x, y);
sub.calculate();
return 0;
}
C++ 解法, 执行用时: 2ms, 内存消耗: 404KB, 提交时间: 2022-02-09
#include <iostream>
using namespace std;
class Base {
private:
int x;
int y;
public:
Base(int x, int y) {
this->x = x;
this->y = y;
}
int getX() {
return x;
}
int getY() {
return y;
}
void calculate() {
cout << getX() * getY() << endl;
}
};
class Sub : public Base {
// write your code here......
public:
Sub(int x,int y):Base(x,y){}
void calculate() {
if(getY()==0)
{
cout << "Error" << endl;
}
else
{
cout << getX()/getY() << endl;
}
}
};
int main() {
int x, y, z;
cin >> x;
cin >> y;
Sub sub(x, y);
sub.calculate();
return 0;
}
C++ 解法, 执行用时: 2ms, 内存消耗: 408KB, 提交时间: 2021-11-21
#include <iostream>
using namespace std;
class Base {
private:
int x;
int y;
public:
Base(int x, int y) {
this->x = x;
this->y = y;
}
int getX() {
return x;
}
int getY() {
return y;
}
void calculate() {
cout << getX() * getY() << endl;
}
};
class Sub : public Base {
// write your code here......
public:
Sub(int x,int y):Base(x,y){
}
void calculate() {
if(getY())
cout << getX() / getY() << endl;
else cout << "Error";
}
};
int main() {
int x, y, z;
cin >> x;
cin >> y;
Sub sub(x, y);
sub.calculate();
return 0;
}
C++ 解法, 执行用时: 2ms, 内存消耗: 412KB, 提交时间: 2022-02-08
#include <iostream>
using namespace std;
class Base {
private:
int x;
int y;
public:
Base(int x, int y) {
this->x = x;
this->y = y;
}
int getX() {
return x;
}
int getY() {
return y;
}
void calculate() {
cout << getX() * getY() << endl;
}
};
class Sub : public Base {
// write your code here......
public:
Sub(int x , int y)
:Base(x,y)
{}
void calculate() {
if(getY()==0){
cout << "Error";
return;
}
cout << getX() / getY() << endl;
}
};
int main() {
int x, y, z;
cin >> x;
cin >> y;
Sub sub(x, y);
sub.calculate();
return 0;
}
C++ 解法, 执行用时: 2ms, 内存消耗: 412KB, 提交时间: 2021-11-13
#include <iostream>
using namespace std;
class Base {
private:
int x;
int y;
public:
Base(int x, int y) {
this->x = x;
this->y = y;
}
int getX() {
return x;
}
int getY() {
return y;
}
void calculate() {
cout << getX() * getY() << endl;
}
};
class Sub : public Base {
// write your code here......
public:
Sub(int x,int y) : Base(x,y){}
void calculate(){
if(getY()){
cout<<getX()/getY()<<endl;
}
else{
cout<<"Error"<<endl;
}
}
};
int main() {
int x, y, z;
cin >> x;
cin >> y;
Sub sub(x, y);
sub.calculate();
return 0;
}