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1841. 联赛信息统计

表: Teams

+----------------+---------+
| Column Name    | Type    |
+----------------+---------+
| team_id        | int     |
| team_name      | varchar |
+----------------+---------+
team_id 是该表主键.
每一行都包含了一个参加联赛的队伍信息.

 

表: Matches

+-----------------+---------+
| Column Name     | Type    |
+-----------------+---------+
| home_team_id    | int     |
| away_team_id    | int     |
| home_team_goals | int     |
| away_team_goals | int     |
+-----------------+---------+
(home_team_id, away_team_id) 是该表主键.
每一行包含了一次比赛信息.
home_team_goals 代表主场队得球数.
away_team_goals 代表客场队得球数.
获得球数较多的队伍为胜者队伍.

 

写一段SQL,用来报告联赛信息. 统计数据应使用已进行的比赛来构建,其中 获胜 球队获得 三分 ,而失败球队获得 零分 。如果 打平 ,两支球队都得 一分 

result 表的每行应包含以下信息:

points 降序 返回结果表。 如果两队或多队得分相同,则按 goal_diff 降序 排列。 如果仍然存在平局,则以 team_name 按字典顺序 排列它们。

查询的结果格式如下例所示。

 

示例 1:

输入:
Teams 表:
+---------+-----------+
| team_id | team_name |
+---------+-----------+
| 1       | Ajax      |
| 4       | Dortmund  |
| 6       | Arsenal   |
+---------+-----------+
Matches 表:
+--------------+--------------+-----------------+-----------------+
| home_team_id | away_team_id | home_team_goals | away_team_goals |
+--------------+--------------+-----------------+-----------------+
| 1            | 4            | 0               | 1               |
| 1            | 6            | 3               | 3               |
| 4            | 1            | 5               | 2               |
| 6            | 1            | 0               | 0               |
+--------------+--------------+-----------------+-----------------+
输出:
+-----------+----------------+--------+----------+--------------+-----------+
| team_name | matches_played | points | goal_for | goal_against | goal_diff |
+-----------+----------------+--------+----------+--------------+-----------+
| Dortmund  | 2              | 6      | 6        | 2            | 4         |
| Arsenal   | 2              | 2      | 3        | 3            | 0         |
| Ajax      | 4              | 2      | 5        | 9            | -4        |
+-----------+----------------+--------+----------+--------------+-----------+
解释:
Ajax (team_id=1) 有4场比赛: 2败2平. 总分数 = 0 + 0 + 1 + 1 = 2.
Dortmund (team_id=4) 有2场比赛: 2胜. 总分数 = 3 + 3 = 6.
Arsenal (team_id=6) 有2场比赛: 2平. 总分数 = 1 + 1 = 2.
Dortmund 是积分榜上的第一支球队. Ajax和Arsenal 有同样的分数, 但Arsenal的goal_diff高于Ajax, 所以Arsenal在表中的顺序在Ajaxzhi'qian.

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# Write your MySQL query statement below

mysql 解法, 执行用时: 690 ms, 内存消耗: 0 B, 提交时间: 2023-10-15 23:08:53

SELECT distinct team_name, 
    COUNT(*) AS matches_played,
    SUM(
        CASE 
        WHEN (team_id=home_team_id AND home_team_goals>away_team_goals) OR
             (team_id=away_team_id AND home_team_goals<away_team_goals) THEN 3
        WHEN (team_id=home_team_id AND home_team_goals<away_team_goals) OR 
             (team_id=away_team_id AND home_team_goals>away_team_goals) THEN 0 
        ELSE 1 END) AS points, 
    SUM(IF(team_id=home_team_id,home_team_goals,away_team_goals)) AS goal_for,
    SUM(IF(team_id=home_team_id,away_team_goals,home_team_goals)) AS goal_against,
    SUM(IF(team_id=home_team_id,home_team_goals,away_team_goals)) - SUM(IF(team_id=home_team_id,away_team_goals,home_team_goals)) AS goal_diff
FROM Teams JOIN Matches ON team_id=home_team_id OR team_id=away_team_id
GROUP BY team_id
ORDER BY points DESC, goal_diff DESC, team_name ASC

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