pypy3 解法, 执行用时: 94ms, 内存消耗: 39896K, 提交时间: 2023-04-05 21:48:08

t=int(input())
for q in range(t):
    n=int(input())
    print('-'*(n-1)+'>')
    x=n-2
    for i in range(n-2):
        for j in range(n):
            if j==x:
                print('/',end='')
            else:
                print('.',end='')
        x-=1
        print()
    print('<'+'-'*(n-1))

Python3 解法, 执行用时: 29ms, 内存消耗: 4524K, 提交时间: 2022-01-01 21:34:45

[print('-'*(n:=int(input())-1)+'>\n'+''.join(['.'*(n-i)+'/'+'.'*i+'\n' for i in range(1,n)])+'<'+'-'*n)for _ in range(int(input()))]