PHP 解法, 执行用时: 19ms, 内存消耗: 7032K, 提交时间: 2023-08-11 11:34:06

<?php

$n = intval(fgets(STDIN));
for ( $i = 0; $i < $n; $i++ ) {
    $k = intval(fgets(STDIN));
    $late = $miss = 0;
    for ( $j = 0; $j < $k; $j++ ) {
        $arr = explode(':', fgets(STDIN));
        $m = intval($arr[0]) * 60 + intval($arr[1]);
        if ( $m < 481 ) {
            continue;
        } elseif ( $m < 486 ) {
            $late++;
        } else {
            $miss++;
        }
    }
    echo "{$late} {$miss}" . PHP_EOL;
}

Python3 解法, 执行用时: 119ms, 内存消耗: 8780K, 提交时间: 2023-08-11 11:30:56

n = int(input())
for i in range(n):
    k = int(input())
    late, miss = 0, 0
    for j in range(k):
        a, b = map(int, input().split(':'))
        m = a * 60 + b 
        if m < 481:
            pass
        elif m < 486:
            late += 1
        else:
            miss += 1
    print(late, miss)

Go 解法, 执行用时: 131ms, 内存消耗: 1748K, 提交时间: 2023-08-11 11:26:21

package main

import "fmt"

func solve() {
	var n, ans, res, a, b int
	fmt.Scan(&n)
	for n > 0 {
		fmt.Scanf("%d:%d", &a, &b)
		if a == 8 {
			if b > 5 {
				res++
			} else if b != 0 {
				ans++
			}
        } else if a > 8 {
            res++
        }
        n--
	}
	fmt.Printf("%d %d\n", ans, res)
}
func main() {
	var time int
	fmt.Scan(&time)
	for time > 0 {
		solve()
		time--
	}
}