Python3(3.9) 解法, 执行用时: 20ms, 内存消耗: 2824K, 提交时间: 2021-03-22 09:44:05

def dw(x):
    if x>=3000:
        return 'Legendary Grandmaster'
    elif x>=2400:
        return 'Grandmaster'
    elif x>=2100:
        return 'Master'
    elif x>=1900:
        return 'Candidate Master'
    elif x>=1600:
        return 'Expert'
    elif x>=1400:
        return 'Specialist'
    elif x>=1200:
        return 'Pupil'
    else:return 'Newbie'
for _ in range(int(input())):
    a,b=map(int,input().split())
    if dw(a)==dw(b):
        print('No')
    else:
        print(dw(a),'to',dw(b))

C++(clang++11) 解法, 执行用时: 3ms, 内存消耗: 396K, 提交时间: 2021-03-25 20:53:35

#include<bits/stdc++.h>
using namespace std;
string s;
string fun(int n){
	if(n>=3000)return "Legendary Grandmaster";
	if(n>=2400)return "Grandmaster";
	if(n>=2100)return "Master";
	if(n>=1900)return "Candidate Master";
	if(n>=1600)return "Expert";
	if(n>=1400)return "Specialist";
	if(n>=1200)return "Pupil";
	return "Newbie";
}
int main(){
	int t;
	int a,b;
	cin>>t;
	while(t--){
		cin>>a>>b;
		if(fun(a)!=fun(b)){
			cout<<fun(a)<<" to "<<fun(b)<<endl;
		}else{
			cout<<"No"<<endl;
		}
	}
}