Java(javac 1.8) 解法, 执行用时: 33ms, 内存消耗: 12212K, 提交时间: 2021-03-21 21:53:03

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		long a =sc.nextLong();
		long b =sc.nextLong();
		long c =sc.nextLong();
		long n =10*10*10*10*10*10*10;
		long ans = 0;
		long y;
		if(a<=n&&b<=n&&c<=n&&a>=0&&b>=0&&c>=0)
		{for(long x=0;x<=a;x++)
		{
			y = c-x;
			
			if(y>b)
				ans =ans+b+1;
			else if(y>=0&&y<=b)
				ans = ans +y+1;
			
		}
		System.out.print(ans);}
			
	}

	

}

C++(clang++11) 解法, 执行用时: 7ms, 内存消耗: 532K, 提交时间: 2021-03-24 16:15:21

#include<bits/stdc++.h>
using namespace std;
signed main()
{
	int a,b,c;
	cin>>a>>b>>c;
	long long ans=0,mn=min(a+b,c);
	for(int z=0;z<=mn;z++)
	ans=ans+(min(z,b)-max(0,z-a)+1);
	cout<<ans<<endl;
	return 0;
}