C(clang 3.9) 解法, 执行用时: 61ms, 内存消耗: 2452K, 提交时间: 2018-12-08 22:28:25

#include<stdio.h>
int main()
{
	long long int n;
	while(scanf("%lld",&n)!=EOF)
	{
		if(n%2==0||n%3==0||n%5==0||n%7==0)
		printf("or2 %lld\n",n/2+n/3+n/5+n/7-n/6-n/10-n/14-n/15-n/21-n/35+n/30+n/42+n/70+n/105-n/210);
		else
		printf("Scum\n");
	}
	return 0;
}

C++11(clang++ 3.9) 解法, 执行用时: 48ms, 内存消耗: 2540K, 提交时间: 2020-02-14 23:04:08

#include<stdio.h>
int main()
{
	long long n;
	while(~scanf("%lld",&n))
	if(n%2!=0&&n%3!=0&&n%5!=0&&n%7!=0) printf("Scum\n");
	else 
	printf("or2 %lld\n",n/2+n/3+n/5+n/7-n/6-n/10-n/14-n/15-n/21-n/35+n/30+n/42+n/70+n/105-n/210);
	
}

C++14(g++5.4) 解法, 执行用时: 52ms, 内存消耗: 2400K, 提交时间: 2019-02-10 00:52:17

#include<stdio.h>
int main(){long long n;while(~scanf("%lld",&n))if(n%2&&n%3&&n%5&&n%7)printf("Scum\n");else printf("or2 %lld\n",n/2+n/3+n/5+n/7-n/6-n/10-n/14-n/15-n/21-n/35+n/30+n/42+n/70+n/105-n/210);return 0;}