C++(clang++ 11.0.1) 解法, 执行用时: 2ms, 内存消耗: 384K, 提交时间: 2023-05-07 14:39:19

#include<bits/stdc++.h>
using namespace std;
void change(char *a){
	string b=a;
	for(int i=0;i<b.size();i++){
		if((a[i]=='M'||a[i]=='m')&&(a[i+1]=='a'||a[i+1]=='A')&&(a[i+2]=='r'||a[i+2]=='R')){
			b.replace(i,9,"fjxmlhx");
		}
	}
	cout<<b<<endl;
}
int main(){
	char a[100];
	while(cin.getline(a,100)){
		change(a);
	}
	return 0;
}

Java(javac 1.8) 解法, 执行用时: 27ms, 内存消耗: 12276K, 提交时间: 2021-03-20 10:12:47

import java.util.Scanner;
public class Main {
    public static void main(String[] args) {
    	Scanner scanner= new Scanner(System.in);
    	while (scanner.hasNextLine()) {
    	String string=scanner.nextLine();
    	System.out.println(string.replaceAll( "(?i)"+"Marshtomp", "fjxmlhx"));
	}
    	}
}

pypy3(pypy3.6.1) 解法, 执行用时: 108ms, 内存消耗: 27632K, 提交时间: 2020-12-13 14:28:01

import re
reg = re.compile(re.escape('marshtomp'), re.IGNORECASE)
while True:
    try:
        a = input()
        a = re.sub('marshtomp','fjxmlhx',a,flags = re.IGNORECASE)
        print(a)
    except:
        break