C(clang11) 解法, 执行用时: 14ms, 内存消耗: 1400K, 提交时间: 2020-12-26 16:00:25

#include<stdio.h>
#include<string.h>
void work(int size,int line)
{
	int mline=8+size*2;
	int i;
	if(size==0)
		{
			if(line==1||line==8)
				printf(".");
			if(line==2||line==7)
				printf("..*..");
			if(line==3||line==6)
				printf("..*.*..");
			if(line==4||line==5)
				printf(".*...*.");
		}
	else
		{
			if(line==1||line==mline)
				{
					if(size%2==1)
						printf("*");
					else
						printf(".");
				}
			else if(line==2||line==3||line==mline-1||line==mline-2)
				{
					if(size%2==1)
						{
							for(i=0; i<2+size; i++)
								printf("*");
							work(size-1,line-1);
							for(i=0; i<2+size; i++)
								printf("*");
						}
					else
						{
							for(i=0; i<2+size; i++)
								printf(".");
							work(size-1,line-1);
							for(i=0; i<2+size; i++)
								printf(".");
						}
				}
			else if(size%2==1)
				{
					printf("**");
					work(size-1,line-1);
					printf("**");
				}
			else
				{
					printf("..");
					work(size-1,line-1);
					printf("..");
				}
		}
}
int main(void)
{
	int n,line,mline,i;
	while((scanf("%d",&n))!=EOF)
		{
			mline=8+n*2;
			for(line=1; line<=mline; line++)
				{
					printf("|");
					if(line<3||line>mline-2)
						for(i=0; i<n+1; i++)
							printf(" ");
					if(line==1||line==mline)
						for(i=0; i<n+2; i++)
							printf(" ");
					work(n,line);
					if(line<3||line>mline-2)
						for(i=0; i<n+1; i++)
							printf(" ");
					if(line==1||line==mline)
						for(i=0; i<n+2; i++)
							printf(" ");
					printf("\n");
				}
		}
	return 0;
}

C++(clang++11) 解法, 执行用时: 12ms, 内存消耗: 1860K, 提交时间: 2020-12-26 14:56:55

#include <stdio.h>


char s[300][2000];
int t[300];
int main() 
{
	int n;
	while (scanf("%d", &n) != EOF) 
	{
		n += 3;
		for (int i = 0; i < 200; ++ i) 
		{
			for (int j = 0; j < 1500; ++ j) 
			{
				s[i][j] = ' ';
			}
			t[i] = 0;
		}
		s[3][0] = '.';
		s[2][0] = '*';s[2][1] = '.';s[2][2] = '.';
		s[1][0] = '.';s[1][1] = '*';s[1][2] = '.';s[1][3] = '.';
		s[0][0] = '.';s[0][1] = '.';s[0][2] = '*';s[0][3] = '.';		
		t[0] = 4;
		t[1] = 4;
		t[2] = 3;
		t[3] = 1;
		for (int i = 4; i <= n; ++ i) 
		{
			char ch;
			if (i & 1) ch = '.';
			else ch = '*';
			s[i][t[i]++] = ch;
			for (int j = 0; j < i-1; ++ j) 
			{
				s[i-1][t[i-1]++] = ch;
			}
			for (int j = 0; j < i-1; ++ j) 
			{
				s[i-2][t[i-2]++] = ch;
			}
			for (int j = i-3; j >= 0; -- j) 
			{
				for (int k = 0; k < 2; ++ k) 
				{
					s[j][t[j]++] = ch;
				}
			}
		} 
		for (int i = n; i >= 0; -- i) 
		{
			printf("|");
			for (int j = (n-2)*2+1; j > 0; -- j) 
			{
				printf("%c", s[i][j]);
			}
			for (int j = 0; j < t[i]; ++ j) 
			{
				printf("%c", s[i][j]);
			}
			printf("\n");
		}
		for (int i = 0; i <= n; ++ i) 
		{
			printf("|");
			for (int j = (n-2)*2+1; j > 0; -- j) 
			{
				printf("%c", s[i][j]);
			}
			for (int j = 0; j < t[i]; ++ j) 
			{
				printf("%c", s[i][j]);
			}
			printf("\n");
		}
	}
	return 0;
}

pypy3(pypy3.6.1) 解法, 执行用时: 79ms, 内存消耗: 50228K, 提交时间: 2020-12-26 14:35:57

source = [
  '     *     ',
  '  ***.***  ',
  '***..*..***',
  '**..*.*..**',
  '**.*...*.**',
  '**.*...*.**',
  '**..*.*..**',
  '***..*..***',
  '  ***.***  ',
  '     *     ',
]

ans = [None, source]

a, b = '.', '*'

res = source.copy()

for i in range(2, 55):
  res[0] = ' ' * (i + 1) + a * (i + 2) + b + a * (i + 2) + ' ' * (i + 1)
  res[-1] = res[0]
  for j in range(1, len(res) - 1):
    res[j] = a * 2 + res[j].replace(' ', a) + a * 2
  push = ' ' * (2 * i + 3) + a + ' ' * (2 * i + 3)
  res = [push] + res + [push]
  a, b = b, a
  ans.append(res.copy())


try:
  while True:
    n = int(input())
    for s in ans[n]:
      print('|' + s)
except EOFError:
  pass