EndAsGPA

NC206677. EndAsGPA

描述

At the end of term, Makise Von got a poor grade.

Meanwhile, EndA started to show his magic.

Now Makise Von wonders if EndA's GPA is really 4.0, and he has almost made it.

There are n exams, and EndA's score of the i-th exam is ai .

Beside, it's known that the i-th exam's proportion of the GPA is pi% .

So let EndA's GPA be ans , then

$ans=4\%\cdot\sum_{i=1}^np_i\%\cdot a_i$

Help Makise Von judge that if EndA's GPA is 4.0.

输入描述

The first line of the input contains a single interger number n (1 <= n <= 20).
The second line of the input contains n interger numbers a1, a2, ..., an (0 <= ai <= 10^2), which are separated by spaces.
The third line of the input contains n interger numbers p1, p2, ..., pn (0 <= pi <= 10^2), which are separated by spaces.
It is guaranteed that , and the absolute error of the answer should be less than 10^(-2).

输出描述

If EndA's GPA is 4.0 print Yes, else print No (without quotes).

示例1

输入:

2
49 71
91 9

输出:

No

示例2

输入:

3
100 100 100
28 25 47

输出:

Yes

原站题解

上次编辑到这里，代码来自缓存点击恢复默认模板

Python3(3.5.2) 解法, 执行用时: 25ms, 内存消耗: 3556K, 提交时间: 2020-06-13 14:12:42

n=eval(input())
list1 = list(map(int,input().split()))
list2 = list(map(int,input().split()))
sum=0
for i in range(n):
    sum+=list1[i]*list2[i]
if sum>=9998:
    print("Yes")
else:
    print("No")

pypy3(pypy3.6.1) 解法, 执行用时: 68ms, 内存消耗: 24248K, 提交时间: 2020-06-13 16:13:09

input()
ans = sum(list(map(lambda x, y : x * y / 100, [int(i) for i in input().split()], [int(i) for i in input().split()]))) / 25
print("Yes" if ans < 4.01 and ans > 3.99 else "No")

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