pypy3 解法, 执行用时: 183ms, 内存消耗: 59296K, 提交时间: 2023-03-28 17:24:19

import sys
def main():
    lines = sys.stdin.readlines()
    code = ''.join(lines)
    i = 0
    code_len = len(code)
    in_str = 0
    while i < code_len:
        if code[i] == '"' and (i == 0 or code[i - 1] != '\\'):
            in_str ^= 1
        if in_str == 0 and code[i] == '/' and i + 3 < code_len and code[i + 1] == '*':
            end = code.find("*/",i+2)
            if end != -1:
                i = end + 2
                continue
        print(code[i], end = '')
        i += 1
if __name__ == '__main__':
    main()

C++14(g++5.4) 解法, 执行用时: 3ms, 内存消耗: 408K, 提交时间: 2020-10-12 23:14:42

#include <cstdio>

#include <regex>

#include <string>

using namespace std;

int main() {

    string code;

    regex r("^((?:[^/\\\\\"]|/[^*]|\\\\\"|\\\\(?!\")|\"(?:\\\\[\\s\\S]|[^\\\\\"])*\")*)/\\*[\\s\\S]*?\\*/");

    for (int c; (c = getchar()) != -1;) code.push_back(c);

    auto pos = code.cbegin();

    for (smatch m; regex_search(pos, code.cend(), m, r); pos = m.suffix().first) {

        printf("%s", m.str(1).c_str());

    }

    while (pos != code.cend()) putchar(*pos++);

}

C++ 解法, 执行用时: 3ms, 内存消耗: 396K, 提交时间: 2021-09-05 19:06:16

#include<bits/stdc++.h>
using namespace std;
int main(){
    string code;
    regex r("^((?:[^/\\\\\"]|/[^*]|\\\\\"|\\\\(?!\")|\"(?:\\\\[\\s\\S]|[^\\\\\"])*\")*)/\\*[\\s\\S]*?\\*/");
    for (int c; (c = getchar()) != -1;) code.push_back(c);
    auto pos = code.cbegin();
    for (smatch m; regex_search(pos, code.cend(), m, r); pos = m.suffix().first) printf("%s", m.str(1).c_str());
    while (pos != code.cend()) putchar(*pos++);
}