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SQL136. 每类试卷得分前3名

描述

现有试卷信息表examination_info(exam_id试卷ID, tag试卷类别, difficulty试卷难度, duration考试时长, release_time发布时间):
id exam_id tag difficulty duration
release_time
1 9001 SQL hard 60 2021-09-01 06:00:00
2 9002 SQL
hard
60
2021-09-01 06:00:00
3 9003
算法
medium
80
2021-09-01 10:00:00

试卷作答记录表exam_record(uid用户ID, exam_id试卷ID, start_time开始作答时间, submit_time交卷时间, score得分)
id uid exam_id start_time submit_time score
1 1001 9001
2021-09-01 09:01:01
2021-09-01 09:31:00 78
2 1002
9001
2021-09-01 09:01:01
2021-09-01 09:31:00 81
3 1002
9002
2021-09-01 12:01:01
2021-09-01 12:31:01 81
4 1003
9001
2021-09-01 19:01:01
2021-09-01 19:40:01 86
5 1003 9002
2021-09-01 12:01:01
2021-09-01 12:31:51
89
6
1004 9001
2021-09-01 19:01:01
2021-09-01 19:30:01
85
7
1005 9003
2021-09-01 12:01:01
2021-09-01 12:31:02
85
8 1006
9003
2021-09-07 10:01:01
2021-09-07 10:21:01
84
9 1003 9003
2021-09-08 12:01:01
2021-09-08 12:11:01
40
10 1003
9002
2021-09-01 14:01:01
(NULL)
(NULL)
找到每类试卷得分的前3名,如果两人最大分数相同,选择最小分数大者,如果还相同,选择uid大者。由示例数据结果输出如下:
tid uid ranking
SQL 1003 1
SQL 1004 2
SQL 1002 3
算法 1005 1
算法
1006 2
算法
1003
3

解释:有作答得分记录的试卷tag有SQL和算法,SQL试卷用户1001、1002、1003、1004有作答得分,最高得分分别为81、81、89、85,最低得分分别为78、81、86、40,因此先按最高得分排名再按最低得分排名取前三为1003、1004、1002。

示例1

输入:

drop table if exists examination_info,exam_record;
CREATE TABLE examination_info (
    id int PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID',
    exam_id int UNIQUE NOT NULL COMMENT '试卷ID',
    tag varchar(32) COMMENT '类别标签',
    difficulty varchar(8) COMMENT '难度',
    duration int NOT NULL COMMENT '时长',
    release_time datetime COMMENT '发布时间'
)CHARACTER SET utf8 COLLATE utf8_general_ci;

CREATE TABLE exam_record (
    id int PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID',
    uid int NOT NULL COMMENT '用户ID',
    exam_id int NOT NULL COMMENT '试卷ID',
    start_time datetime NOT NULL COMMENT '开始时间',
    submit_time datetime COMMENT '提交时间',
    score tinyint COMMENT '得分'
)CHARACTER SET utf8 COLLATE utf8_general_ci;

INSERT INTO examination_info(exam_id,tag,difficulty,duration,release_time) VALUES
  (9001, 'SQL', 'hard', 60, '2021-09-01 06:00:00'),
  (9002, 'SQL', 'hard', 60, '2021-09-01 06:00:00'),
  (9003, '算法', 'medium', 80, '2021-09-01 10:00:00');

INSERT INTO exam_record(uid,exam_id,start_time,submit_time,score) VALUES
(1001, 9001, '2021-09-01 09:01:01', '2021-09-01 09:31:00', 78),
(1001, 9001, '2021-09-01 09:01:01', '2021-09-01 09:31:00', 81),
(1002, 9002, '2021-09-01 12:01:01', '2021-09-01 12:31:01', 81),
(1003, 9001, '2021-09-01 19:01:01', '2021-09-01 19:40:01', 86),
(1003, 9002, '2021-09-01 12:01:01', '2021-09-01 12:31:51', 89),
(1004, 9001, '2021-09-01 19:01:01', '2021-09-01 19:30:01', 85),
(1005, 9003, '2021-09-01 12:01:01', '2021-09-01 12:31:02', 85),
(1006, 9003, '2021-09-07 10:01:01', '2021-09-07 10:21:01', 84),
(1003, 9003, '2021-09-08 12:01:01', '2021-09-08 12:11:01', 40),
(1003, 9002, '2021-09-01 14:01:01', null, null);

输出:

SQL|1003|1
SQL|1004|2
SQL|1002|3
算法|1005|1
算法|1006|2
算法|1003|3

原站题解

上次编辑到这里,代码来自缓存 点击恢复默认模板

Mysql 解法, 执行用时: 36ms, 内存消耗: 6388KB, 提交时间: 2021-12-27

select tag,uid,rk
from (
    select tag, uid, rank() over (partition by tag order by tag,max(score) desc,min(score) desc,uid desc) as rk
    from exam_record er left join examination_info ei on er.exam_id = ei.exam_id
    group by tag,uid
) as t
where rk<=3

Mysql 解法, 执行用时: 36ms, 内存消耗: 6400KB, 提交时间: 2022-01-25

select tag,uid,ranking
 from (
 select tag,uid,row_number()over(partition by tag 
                                 order by tag,max(score)desc,min(score) desc,uid desc ) as ranking
 from  exam_record er 
 left join examination_info ei on er.exam_id=ei.exam_id
 group by tag,uid
 )test
 where ranking <=3
 

Mysql 解法, 执行用时: 36ms, 内存消耗: 6472KB, 提交时间: 2021-12-19

select tag,uid,ranking
from (
    select tag,uid,ROW_NUMBER()OVER(PARTITION BY tag ORDER BY MAX(score) DESC,MIN(score)DESC,uid DESC) ranking
    from exam_record er
    join examination_info ei using(exam_id)
    group by tag,uid
) as t1
where ranking<=3

Mysql 解法, 执行用时: 36ms, 内存消耗: 6504KB, 提交时间: 2022-01-03

WITH t AS
(SELECT info.tag tag, er.uid uid, max(er.score) max_score, min(er.score) min_score
FROM examination_info info JOIN exam_record er ON info.exam_id = er.exam_id
WHERE score IS NOT NULL
GROUP BY info.tag, er.uid)

SELECT * FROM
(SELECT tag, uid, ROW_NUMBER() OVER (PARTITION BY tag ORDER BY max_score DESC, min_score DESC, uid DESC) r_rank
FROM t) a
WHERE a.r_rank <= 3

Mysql 解法, 执行用时: 36ms, 内存消耗: 6512KB, 提交时间: 2021-12-07

select *
FROM
(select 
    ei.tag,
    er.uid,
    ROW_NUMBER() over(partition by ei.tag order by tag,
                          max(score) desc,
                          min(score) desc,
                          er.uid DESC) as rk
from examination_info as ei
join exam_record as er
on ei.exam_id = er.exam_id
group by tag,er.uid) as a
where rk <= 3

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