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SQL131. 作答试卷得分大于过80的人的用户等级分布

描述

现有用户信息表user_info(uid用户ID,nick_name昵称, achievement成就值, level等级, job职业方向, register_time注册时间):
id uid nick_name achievement level job register_time
1 1001
牛客1号
3100
7 算法
2020-01-01 10:00:00
2 1002
牛客2号
2100
6 算法
2020-01-01 10:00:00
3 1003
牛客3号
1500
5 算法
2020-01-01 10:00:00
4 1004
牛客4号
1100 4 算法
2020-01-01 10:00:00
5 1005 牛客5号
1600
6 C++
2020-01-01 10:00:00
6 1006 牛客6号
3000
6 C++ 2020-01-01 10:00:00

试卷信息表examination_info(exam_id试卷ID, tag试卷类别, difficulty试卷难度, duration考试时长, release_time发布时间):
id exam_id tag difficulty duration
release_time
1 9001 SQL hard 60 2021-09-01 06:00:00
2 9002 C++ easy
60
2021-09-01 06:00:00
3 9003
算法
medium
80
2021-09-01 10:00:00

试卷作答信息表exam_record(uid用户ID, exam_id试卷ID, start_time开始作答时间, submit_time交卷时间, score得分):
id uid exam_id start_time submit_time score
1 1001 9001
2021-09-01 09:01:01
2021-09-01 09:41:01
79
2 1002
9003
2021-09-01 12:01:01
2021-09-01 12:21:01 60
3 1002
9002
2021-09-01 12:01:01
2021-09-01 12:31:01 70
4 1002
9001
2021-09-01 19:01:01
2021-09-01 19:40:01 80
5 1002
9003
2021-08-01 12:01:01
2021-08-01 12:21:01
60
6 1002
9002
2021-09-01 12:01:01
2021-09-01 12:31:01 70
7 1002 9001
2021-09-01 19:01:01
2021-09-01 19:40:01
85
8 1002 9002
2021-09-01 12:01:01
(NULL)
(NULL)
9 1003
9003
2021-09-07 10:01:01
2021-09-07 10:31:01
86
10 1003
9003
2021-09-08 12:01:01
2021-09-08 12:11:01
40
11 1003
9001
2021-09-01 13:01:01 2021-09-01 13:41:01
81
12 1003
9002
2021-09-01 14:01:01
(NULL)
(NULL)
13 1003
9003
2021-09-08 15:01:01
(NULL)
(NULL)
14
1005
9001
2021-09-01 12:01:01
2021-09-01 12:31:01
90
15 1005
9002
2021-09-01 12:01:01
2021-09-01 12:31:01
88
16 1006
9002
2021-09-01 12:11:01 2021-09-01 12:31:01
89

统计作答SQL类别的试卷得分大于过80的人的用户等级分布,按数量降序排序(保证数量都不同)。示例数据结果输出如下:
level level_cnt
6 2
5 1
解释:9001为SQL类试卷,作答该试卷大于80分的人有1002、1003、1005共3人,6级两人,5级一人。

示例1

输入:

drop table if exists examination_info;
CREATE TABLE examination_info (
    id int PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID',
    exam_id int UNIQUE NOT NULL COMMENT '试卷ID',
    tag varchar(32) COMMENT '类别标签',
    difficulty varchar(8) COMMENT '难度',
    duration int NOT NULL COMMENT '时长',
    release_time datetime COMMENT '发布时间'
)CHARACTER SET utf8 COLLATE utf8_general_ci;

drop table if exists user_info;
CREATE TABLE user_info (
    id int PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID',
    uid int UNIQUE NOT NULL COMMENT '用户ID',
    `nick_name` varchar(64) COMMENT '昵称',
    achievement int COMMENT '成就值',
    level int COMMENT '用户等级',
    job varchar(32) COMMENT '职业方向',
    register_time datetime COMMENT '注册时间'
)CHARACTER SET utf8 COLLATE utf8_general_ci;

drop table if exists exam_record;
CREATE TABLE  exam_record (
    id int PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID',
    uid int NOT NULL COMMENT '用户ID',
    exam_id int NOT NULL COMMENT '试卷ID',
    start_time datetime NOT NULL COMMENT '开始时间',
    submit_time datetime COMMENT '提交时间',
    score tinyint COMMENT '得分'
)CHARACTER SET utf8 COLLATE utf8_general_ci;

INSERT INTO user_info(uid,`nick_name`,achievement,level,job,register_time) VALUES
  (1001, '牛客1号', 3100, 7, '算法', '2020-01-01 10:00:00'),
  (1002, '牛客2号', 2100, 6, '算法', '2020-01-01 10:00:00'),
  (1003, '牛客3号', 1500, 5, '算法', '2020-01-01 10:00:00'),
  (1004, '牛客4号', 1100, 4, '算法', '2020-01-01 10:00:00'),
  (1005, '牛客5号', 1600, 6, 'C++', '2020-01-01 10:00:00'),
  (1006, '牛客6号', 3000, 6, 'C++', '2020-01-01 10:00:00');

INSERT INTO examination_info(exam_id,tag,difficulty,duration,release_time) VALUES
  (9001, 'SQL', 'hard', 60, '2021-09-01 06:00:00'),
  (9002, 'C++', 'easy', 60, '2021-09-01 06:00:00'),
  (9003, '算法', 'medium', 80, '2021-09-01 10:00:00');

INSERT INTO exam_record(uid,exam_id,start_time,submit_time,score) VALUES
(1001, 9001, '2021-09-01 09:01:01', '2021-09-01 09:41:01', 79),
(1002, 9003, '2021-09-01 12:01:01', '2021-09-01 12:21:01', 60),
(1002, 9002, '2021-09-01 12:01:01', '2021-09-01 12:31:01', 70),
(1002, 9001, '2021-09-01 19:01:01', '2021-09-01 19:40:01', 80),
(1002, 9003, '2021-08-01 12:01:01', '2021-08-01 12:21:01', 60),
(1002, 9002, '2021-09-01 12:01:01', '2021-09-01 12:31:01', 70),
(1002, 9001, '2021-09-01 19:01:01', '2021-09-01 19:40:01', 85),
(1002, 9002, '2021-09-01 12:01:01', null, null),
(1003, 9003, '2021-09-07 10:01:01', '2021-09-07 10:31:01', 86),
(1003, 9003, '2021-09-08 12:01:01', '2021-09-08 12:11:01', 40),
(1003, 9001, '2021-09-01 13:01:01', '2021-09-01 13:41:01', 81),
(1003, 9002, '2021-09-01 14:01:01', null, null),
(1003, 9003, '2021-09-08 15:01:01', null, null),
(1005, 9001, '2021-09-01 12:01:01', '2021-09-01 12:31:01', 90),
(1005, 9002, '2021-09-01 12:01:01', '2021-09-01 12:31:01', 88),
(1006, 9002, '2021-09-01 12:11:01', '2021-09-01 12:31:01', 89);

输出:

6|2
5|1

原站题解

上次编辑到这里,代码来自缓存 点击恢复默认模板

Mysql 解法, 执行用时: 36ms, 内存消耗: 6408KB, 提交时间: 2022-01-03

SELECT level, COUNT(DISTINCT uid) AS level_cnt
FROM exam_record er JOIN user_info ui USING(uid)
JOIN examination_info ei USING(exam_id)
WHERE ei.tag='SQL' AND er.score > 80
GROUP BY level
ORDER BY COUNT(DISTINCT uid) DESC, level DESC

Mysql 解法, 执行用时: 36ms, 内存消耗: 6520KB, 提交时间: 2021-12-07



select ui.level,count(ui.level) as level_cnt
from exam_record as er
join user_info as ui using(uid)
where er.exam_id in (select exam_id FROM examination_info where tag='SQL')
and er.score>80
group by ui.level
order by level_cnt desc

Mysql 解法, 执行用时: 37ms, 内存消耗: 6328KB, 提交时间: 2021-12-08

SELECT level, count(distinct uid) as level_cnt
FROM exam_record
JOIN examination_info USING (exam_id)
JOIN user_info USING (uid)
where score > 80 and tag='SQL'
GROUP BY level
ORDER BY count(DISTINCT uid) DESC, level DESC

Mysql 解法, 执行用时: 37ms, 内存消耗: 6348KB, 提交时间: 2022-01-24

select ui.level as 'level', count(*) as level_cnt
from exam_record as er
join examination_info as ei
on er.exam_id = ei.exam_id
join user_info as ui
on ui.uid = er.uid
where ei.tag = 'SQL' and er.score > 80
group by ui.level
order by level_cnt desc;

Mysql 解法, 执行用时: 37ms, 内存消耗: 6384KB, 提交时间: 2021-12-02

select level,
       count(distinct u_i.uid) as level_cnt
from exam_record e_r join examination_info e_i
on e_r.exam_id = e_i.exam_id
join user_info u_i
on e_r.uid = u_i.uid
where tag = 'SQL'
and score > 80
group by level
order by level_cnt desc, level desc