截取出年龄

示例：user_submit

device_id	profile	blog_url
2138	180cm,75kg,27,male	http:/ur/bigboy777
3214	165cm,45kg,26,female	http:/url/kittycc
6543	178cm,65kg,25,male	http:/url/tiger
4321	171cm,55kg,23,female	http:/url/uhksd
2131	168cm,45kg,22,female	http:/url/sydney

根据示例，你的查询应返回以下结果：

age	number
27	1
26	1
25	1
23	1
22	1

示例1

输入:

drop table if exists user_submit;
CREATE TABLE `user_submit` (
`id` int NOT NULL,
`device_id` int NOT NULL,
`profile` varchar(100) NOT NULL,
`blog_url` varchar(100) NOT NULL
);
INSERT INTO user_submit VALUES(1,2138,'180cm,75kg,27,male','http:/url/bisdgboy777');
INSERT INTO user_submit VALUES(1,3214,'165cm,45kg,26,female','http:/url/dkittycc');
INSERT INTO user_submit VALUES(1,6543,'178cm,65kg,25,male','http:/url/tigaer');
INSERT INTO user_submit VALUES(1,4321,'171cm,55kg,23,female','http:/url/uhsksd');
INSERT INTO user_submit VALUES(1,2131,'168cm,45kg,22,female','http:/url/sysdney');

输出:

27|1
26|1
25|1
23|1
22|1

原站题解

上次编辑到这里，代码来自缓存点击恢复默认模板

Mysql 解法, 执行用时: 36ms, 内存消耗: 6388KB, 提交时间: 2022-02-10

SELECT age,COUNT(*) number
FROM (SELECT SUBSTR(PROFILE,12,2) age
FROM user_submit) ages
GROUP BY age

Mysql 解法, 执行用时: 36ms, 内存消耗: 6404KB, 提交时间: 2021-12-14

SELECT substring_index(substring_index(profile,',',-2),',',1) as age,count(*) as number
from user_submit
group by age;

Mysql 解法, 执行用时: 36ms, 内存消耗: 6416KB, 提交时间: 2022-02-09

SELECT
    substring_index(SUBSTRING_INDEX(profile,',',-2),',',1) age,
    count(*)
FROM user_submit
GROUP BY age

Mysql 解法, 执行用时: 36ms, 内存消耗: 6420KB, 提交时间: 2021-12-27

select SUBSTR(profile,12,2) as age, count(device_id) as number
from user_submit
group by age

Mysql 解法, 执行用时: 36ms, 内存消耗: 6420KB, 提交时间: 2021-12-20

SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(profile,',',3),',',-1) age ,count(device_id) number from user_submit
group by age

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