SQL248. 平均工资
描述
查找排除在职(to_date = '9999-01-01' )员工的最大、最小salary之后,其他的在职员工的平均工资avg_salary。avg_salary |
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73292 |
示例1
输入:
drop table if exists `salaries` ; CREATE TABLE `salaries` ( `emp_no` int(11) NOT NULL, `salary` float(11,3) NOT NULL, `from_date` date NOT NULL, `to_date` date NOT NULL, PRIMARY KEY (`emp_no`,`from_date`)); INSERT INTO salaries VALUES(10001,85097,'2001-06-22','2002-06-22'); INSERT INTO salaries VALUES(10001,88958,'2002-06-22','9999-01-01'); INSERT INTO salaries VALUES(10002,72527,'2001-08-02','9999-01-01'); INSERT INTO salaries VALUES(10003,43699,'2000-12-01','2001-12-01'); INSERT INTO salaries VALUES(10003,43311,'2001-12-01','9999-01-01'); INSERT INTO salaries VALUES(10004,70698,'2000-11-27','2001-11-27'); INSERT INTO salaries VALUES(10004,74057,'2001-11-27','9999-01-01');
输出:
73292.000
Sqlite 解法, 执行用时: 10ms, 内存消耗: 3368KB, 提交时间: 2021-09-22
select avg(salary) from salaries where to_date = '9999-01-01' and ( salary != (select max(salary) from salaries where to_date ='9999-01-01') and salary != (select min(salary) from salaries where to_date = '9999-01-01'))
Sqlite 解法, 执行用时: 10ms, 内存消耗: 3496KB, 提交时间: 2021-09-09
select avg(salary) from salaries where to_date='9999-01-01' and salary not in (select min(salary) from salaries where to_date='9999-01-01') and salary not in (select max(salary) from salaries where to_date='9999-01-01');
Sqlite 解法, 执行用时: 10ms, 内存消耗: 3500KB, 提交时间: 2021-09-08
select avg(salary) as avg_salary from salaries where to_date='9999-01-01' and salary not in (select max(salary) from salaries where to_date='9999-01-01') and salary not in (select min(salary) from salaries where to_date='9999-01-01')
Sqlite 解法, 执行用时: 10ms, 内存消耗: 3500KB, 提交时间: 2021-08-09
select avg(salary) from salaries where to_date = '9999-01-01' and salary not in(select max(salary) from salaries where to_date = '9999-01-01') and salary not in(select min(salary) from salaries where to_date = '9999-01-01')
Sqlite 解法, 执行用时: 10ms, 内存消耗: 3508KB, 提交时间: 2021-09-08
SELECT AVG(s1.salary) AS avg_salary FROM salaries AS s1 WHERE s1.to_date = '9999-01-01' AND s1.salary NOT IN (SELECT MAX(salary) FROM salaries AS s2 WHERE s2.to_date = '9999-01-01') AND s1.saLary NOT IN (SELECT MIN(salary) FROM salaries AS s2 WHERE s2.to_date = '9999-01-01');