emp_no	salary	from_date	to_date
10001	88958	1986-06-26	9999-01-01
10002	72527	1996-08-03	9999-01-01

获取所有非manager员工薪水情况，给出dept_no、emp_no以及salary，以上例子输出:

示例1

输入:

drop table if exists  `dept_emp` ; 
drop table if exists  `dept_manager` ; 
drop table if exists  `employees` ; 
drop table if exists  `salaries` ; 
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
INSERT INTO dept_emp VALUES(10001,'d001','1986-06-26','9999-01-01');
INSERT INTO dept_emp VALUES(10002,'d001','1996-08-03','9999-01-01');
INSERT INTO dept_manager VALUES('d001',10002,'1996-08-03','9999-01-01');
INSERT INTO employees VALUES(10001,'1953-09-02','Georgi','Facello','M','1986-06-26');
INSERT INTO employees VALUES(10002,'1964-06-02','Bezalel','Simmel','F','1996-08-03');
INSERT INTO salaries VALUES(10001,88958,'1986-06-26','9999-01-01');
INSERT INTO salaries VALUES(10002,72527,'1996-08-03','9999-01-01');

输出:

d001|10001|88958

原站题解

select
    t1.dept_no,t1.emp_no,s.salary
from
(
    select
        dept_no,emp_no
    from dept_emp d 
    where d.emp_no not in
    (
        select 
            emp_no
        from dept_manager dm
    )
)t1
inner join salaries s 
on t1.emp_no=s.emp_no

select de.dept_no,e.emp_no ,s.salary
from employees e
left join dept_emp de
on e.emp_no=de.emp_no
left join salaries s
on e.emp_no=s.emp_no
where e.emp_no not in (select emp_no from dept_manager)

select a.dept_no, a.emp_no, b.salary
from dept_emp a, salaries b
where a.emp_no=b.emp_no
and a.emp_no not in (
select emp_no
from dept_manager
)

select b.dept_no,b.emp_no,a.salary from salaries a,dept_emp b 
where a.emp_no = b.emp_no and a.emp_no not in(
select emp_no from dept_manager)

SELECT de.dept_no, de.emp_no, s.salary
FROM dept_emp de INNER JOIN salaries s
ON de.emp_no = s.emp_no
WHERE de.emp_no NOT IN (
SELECT dm.emp_no FROM dept_manager dm);