找出所有员工当前薪水salary情况

emp_no	salary	from_date	to_date
10001	72527	2002-06-22	9999-01-01
10002	72527	2001-08-02	9999-01-01
10003	43311	2001-12-01	9999-01-01

请你找出所有员工具体的薪水salary情况，对于相同的薪水只显示一次,并按照逆序显示，以上例子输出如下:

salary

72527

43311

示例1

输入:

drop table if exists  `salaries` ; 
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
INSERT INTO salaries VALUES(10001,72527,'2002-06-22','9999-01-01');
INSERT INTO salaries VALUES(10002,72527,'2001-08-02','9999-01-01');
INSERT INTO salaries VALUES(10003,43311,'2001-12-01','9999-01-01');

输出:

72527
43311

原站题解

上次编辑到这里，代码来自缓存点击恢复默认模板

Sqlite 解法, 执行用时: 10ms, 内存消耗: 3240KB, 提交时间: 2021-08-03

select salary 
from salaries
group by salary
order by salary desc;

Sqlite 解法, 执行用时: 10ms, 内存消耗: 3260KB, 提交时间: 2021-08-01

select salary
from salaries
where to_date='9999-01-01'
group by salary
order by salary desc

Sqlite 解法, 执行用时: 10ms, 内存消耗: 3300KB, 提交时间: 2020-11-22

select distinct salary
from salaries
where to_date='9999-01-01'
order by salary desc

Sqlite 解法, 执行用时: 10ms, 内存消耗: 3320KB, 提交时间: 2021-06-08

select salary
from salaries where to_date="9999-01-01"
group by salary 
order by salary desc

Sqlite 解法, 执行用时: 10ms, 内存消耗: 3320KB, 提交时间: 2021-06-01

select salary 
from salaries
group by salary
order by salary desc

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