SQL196. 查找入职员工时间排名倒数第三的员工所有信息

描述

示例1

输入:

drop table if exists  `employees` ; 
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
INSERT INTO employees VALUES(10001,'1953-09-02','Georgi','Facello','M','1986-06-26');
INSERT INTO employees VALUES(10002,'1964-06-02','Bezalel','Simmel','F','1985-11-21');
INSERT INTO employees VALUES(10003,'1959-12-03','Parto','Bamford','M','1986-08-28');
INSERT INTO employees VALUES(10004,'1954-05-01','Chirstian','Koblick','M','1986-12-01');
INSERT INTO employees VALUES(10005,'1955-01-21','Kyoichi','Maliniak','M','1989-09-12');
INSERT INTO employees VALUES(10006,'1953-04-20','Anneke','Preusig','F','1989-06-02');
INSERT INTO employees VALUES(10007,'1957-05-23','Tzvetan','Zielinski','F','1989-02-10');
INSERT INTO employees VALUES(10008,'1958-02-19','Saniya','Kalloufi','M','1994-09-15');
INSERT INTO employees VALUES(10009,'1952-04-19','Sumant','Peac','F','1985-02-18');
INSERT INTO employees VALUES(10010,'1963-06-01','Duangkaew','Piveteau','F','1989-08-24');
INSERT INTO employees VALUES(10011,'1953-11-07','Mary','Sluis','F','1990-01-22');

输出:

10005|1955-01-21|Kyoichi|Maliniak|M|1989-09-12

原站题解

select * from
employees 
where 
hire_date =
(select hire_date from employees group by hire_date order by hire_date desc limit 2,1)

select * from employees where hire_date = 
(select hire_date from employees group by hire_date order by hire_date desc limit 2,1)

select * from employees
where hire_date=(
select  hire_date from employees
    group by hire_date
order by hire_date desc
limit 2,1)

select * from employees where hire_date=
(select hire_date from employees group by hire_date order by hire_date desc limit 2,1);

select * from employees where hire_date = (
select hire_date from  employees t  
group by  hire_date order by  hire_date desc  limit 1  offset 2)