HJ95. 人民币转换
描述
考试题目和要点：
1、中文大写金额数字前应标明“人民币”字样。中文大写金额数字应用壹、贰、叁、肆、伍、陆、柒、捌、玖、拾、佰、仟、万、亿、元、角、分、零、整等字样填写。
2、中文大写金额数字到“元”为止的，在“元”之后，应写“整字，如532.00应写成“人民币伍佰叁拾贰元整”。在”角“和”分“后面不写”整字。
输入描述
输入一个double数
输出描述
输出人民币格式
示例1
输入:
151121.15
输出:
人民币拾伍万壹仟壹佰贰拾壹元壹角伍分
示例2
输入:
1010.00
输出:
人民币壹仟零拾元整
C 解法, 执行用时: 1ms, 内存消耗: 268KB, 提交时间: 2021-02-06
#include <stdio.h>
#include <string.h>
char Big_Ch_Num[][4] = { "零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖", "拾" };
char section_unit[][4] = {
"", "拾", "佰", "仟",
"万", "拾", "佰", "仟",
"亿", "拾", "佰", "仟",
"兆", "拾", "佰", "仟",
"京", "拾", "佰", "仟",
"垓", "拾", "佰", "仟",
"秭", "拾", "佰", "仟",
"穰", "拾", "佰", "仟",
"沟", "拾", "佰", "仟",
"涧", "拾", "佰", "仟",
"正", "拾", "佰", "仟",
"载", "拾", "佰", "仟"
};
int main(void)
{
char i, j, k, ch, s[128], len, zero_cnt, jiao, fen;
for( ; scanf("%s", s)!=EOF; ){
printf("人民币");
len = strlen(s);
for(i=len-1; i>=0; i--)
if(s[i] == '.') break;
jiao = fen = 0;
if(i == -1) j=len-1;
else{
j=i-1; i++;
if(i < len){
jiao = s[i++]-48;
if(i < len) fen = s[i]-48;
}
}
i=zero_cnt=0; k=j;
for( ; k>=0; i++,k--){
if((ch=s[i]) != '0'){
if(zero_cnt){ printf("零"); zero_cnt=0; }
if(ch!='1' || k%4!=1) printf("%s", Big_Ch_Num[ ch-48 ]);
printf("%s", section_unit[ k ]);
continue;
}
zero_cnt++;
if(k%4) continue;
if(zero_cnt != 4) printf("%s", section_unit[ k ]);
zero_cnt = 0;
}
if(j || s[j]!='0') printf("元");
else{
if(jiao+fen) goto rpt;
printf("零元整\n"); continue;
}
if(jiao+fen){
rpt: if(jiao) printf("%s角", Big_Ch_Num[ jiao ]);
fen ? printf("%s分\n", Big_Ch_Num[ fen ]) : printf("\n");
}
else printf("整\n");
}
return 0;
}
C 解法, 执行用时: 1ms, 内存消耗: 368KB, 提交时间: 2021-03-02
#include"stdio.h"
int pre=1;
void OutPutNum(int num, int type){
if(type){
if(num>100000000) num/=10000;
if(num<100000000 && num>10000) num/=10000;
switch (num){
case 1 : printf("元"); break;
case 10 : printf("拾"); break;
case 100 : printf("佰"); break;
case 1000 : printf("仟"); break;
case 10000 : printf("万"); break;
case 100000000 : printf("亿"); break;
default: break;
}
return;
}
switch (num){
case 0 : if(pre){printf("零"); pre = 0; }
break;
case 1 : printf("壹"); pre = 1;break;
case 2 : printf("贰"); pre = 1;break;
case 3 : printf("叁"); pre = 1;break;
case 4 : printf("肆"); pre = 1;break;
case 5 : printf("伍"); pre = 1;break;
case 6 : printf("陆"); pre = 1;break;
case 7 : printf("柒"); pre = 1;break;
case 8 : printf("捌"); pre = 1;break;
case 9 : printf("玖"); pre = 1;break;
default: break;
}
}
int main(void){
double n;
while(scanf("%lf", &n) != EOF){
int i,level=1,l=0,value,num,xo;
num = (int)n;
xo = (1000*n - 1000*num)/10;
while(num-level >= 0) level*=10;
printf("人民币");
for(level/=10; level>=1; level/=10){
value = (int)num/level;
num = num%level;
if(value==0 && level==10000){}
else if(value==1 && (level==10|| level==100000)){}
else
OutPutNum(value,0);
if(value || (level==10000) || (level==100000000)) OutPutNum(level,1);
if(0==num && level>1){printf("元");break;}
}
if(xo<1) printf("整");
else{
value = xo/10;
if(value){
OutPutNum(value,0);
printf("角");
}
value = xo%10;
if(value){
OutPutNum(value,0);
printf("分");
}
}
printf("\n");
}
}