C 解法, 执行用时: 2ms, 内存消耗: 376KB, 提交时间: 2020-05-20

#include<stdio.h>
#include<stdlib.h>
void fun(int a, int b) {
    int m ;
    int n ;
    int s = 0;
    m = a;
    n = b;
    int temp1 = 0;
    s = m / n;
    temp1 = s;
    int da[10000];
    int temp = 0;
    for (temp = 0; temp<10000;) {
        m = m % n * 10;
        if (m>0) {
            s = m / n;
            da[temp] = m;
            temp++;
        }
        else {
            break;
        }
    }
    int num = -1;
    int num1 = 0;
    for (int i = 0; i<temp; i++) {
        for (int j = i + 1; j<temp; j++) {
            if (da[i] == da[j]) {
                num1 = i;
                num = j;
                break;
            }
        }
        if (num>-1)
            break;
    }
    if (num > 0) {
        printf("%d", temp1);
        printf(".");
        for (int i = 0; i < num1; i++) {
            m = da[i];
            s = m / n;
            printf("%d", s);
        }
        printf("(");
        for (int i = num1; i < num; i++) {
            m = da[i];
            s = m / n;
            printf("%d", s);
        }
        printf(")");
    }
    else{
        printf("%g", (float)(a) / b);
    }
}
int main() {
    int a;
    int b;
    while(scanf("%d %d",&a, &b) != EOF)
        fun(a,b);
    return 0;
}

C 解法, 执行用时: 2ms, 内存消耗: 376KB, 提交时间: 2020-05-18

#include<stdio.h>
#include<stdlib.h>
void fun(int a, int b) {
    int m ;
    int n ;
    int s = 0;
    m = a;
    n = b;
    int temp1 = 0;
    s = m / n;
    temp1 = s;
    int da[10000];
    int temp = 0;
    for (temp = 0; temp<10000;) {
        m = m % n * 10;
        if (m>0) {
            s = m / n;
            da[temp] = m;
            temp++;
        }
        else {
            break;
        }
    }
    int num = -1;
    int num1 = 0;
    for (int i = 0; i<temp; i++) {
        for (int j = i + 1; j<temp; j++) {
            if (da[i] == da[j]) {
                num1 = i;
                num = j;
                break;
            }
        }
        if (num>-1)
            break;
    }
    if (num > 0) {
        printf("%d", temp1);
        printf(".");
        for (int i = 0; i < num1; i++) {
            m = da[i];
            s = m / n;
            printf("%d", s);
        }
        printf("(");
        for (int i = num1; i < num; i++) {
            m = da[i];
            s = m / n;
            printf("%d", s);
        }
        printf(")");
    }
    else{
        printf("%g", (float)(a) / b);
    }
}
int main() {
    int a;
    int b;
    while(scanf("%d %d",&a, &b) != EOF)
        fun(a,b);
    return 0;
}