C 解法, 执行用时: 2ms, 内存消耗: 368KB, 提交时间: 2020-12-23

#include <stdio.h>
  
int main()
{
    unsigned int A,B,C,x;
    scanf("%d,%d,%d",&A,&B,&C);
    x = A^B^C;
    if(x == 0)
        printf("1\n");
    else
    {
        if((A^B) < C)
            printf("C,%u\n", C-(A^B));
        else if((A^C) < B)
            printf("B,%u\n", B-(A^C));
        else if((B^C) < A)
            printf("A,%u\n", A-(B^C));
    }
}

C 解法, 执行用时: 2ms, 内存消耗: 372KB, 提交时间: 2020-08-19

#include <stdio.h>
  
int main()
{
    unsigned int A,B,C,x;
    scanf("%d,%d,%d",&A,&B,&C);
    x = A^B^C;
    if(x == 0)
        printf("1\n");
    else
    {
        if((A^B) < C)
            printf("C,%u\n", C-(A^B));
        else if((A^C) < B)
            printf("B,%u\n", B-(A^C));
        else if((B^C) < A)
            printf("A,%u\n", A-(B^C));
    }
}

C 解法, 执行用时: 2ms, 内存消耗: 372KB, 提交时间: 2019-05-05

#include <stdio.h>
  
int main()
{
    unsigned int A,B,C,x;
    scanf("%d,%d,%d",&A,&B,&C);
    x = A^B^C;
    if(x == 0)
        printf("1\n");
    else
    {
        if((A^B) < C)
            printf("C,%u\n", C-(A^B));
        else if((A^C) < B)
            printf("B,%u\n", B-(A^C));
        else if((B^C) < A)
            printf("A,%u\n", A-(B^C));
    }
}

C 解法, 执行用时: 2ms, 内存消耗: 376KB, 提交时间: 2020-05-17

#include <stdio.h>
   
int main()
{
    unsigned int A,B,C,x;
    scanf("%d,%d,%d",&A,&B,&C);
    x = A^B^C;
    if(x == 0)
        printf("1\n");
    else
    {
        if((A^B) < C)
            printf("C,%u\n", C-(A^B));
        else if((A^C) < B)
            printf("B,%u\n", B-(A^C));
        else if((B^C) < A)
            printf("A,%u\n", A-(B^C));
    }
}

C 解法, 执行用时: 2ms, 内存消耗: 376KB, 提交时间: 2019-08-14

#include<stdio.h>
int main()
{
    int a,b,c;
    scanf("%d,%d,%d",&a,&b,&c);
    if((a^b^c)==0)
    {
        printf("1");
    }
    else if((a^b)<c)
    {
        printf("C,%d",c-(a^b));
    }
    else if((a^c)<b)
    {
                printf("B,%d",b-(a^c));
    }
    else
    {
             printf("A,%d",a-(b^c));
    }
}