Python 解法, 执行用时: 11ms, 内存消耗: 3084KB, 提交时间: 2022-08-01

my_list = [
    [1,2,3],
    [4,5,6],
    [7,8,9]
]

n = int(input())
for i in my_list:
    for j in range(len(i)):
        i[j] = i[j] * n
print(my_list)

Python 解法, 执行用时: 12ms, 内存消耗: 3016KB, 提交时间: 2022-07-30

my_list = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
res_list = list()
res = list()
n = int(input())
for list_ in my_list:
    for item in list_:
        res_list.append(item * n)
    
    res.append(res_list)
    res_list = list()

print(res)
        

Python 解法, 执行用时: 12ms, 内存消耗: 3176KB, 提交时间: 2022-08-01

list = my_list = [
    [1,2,3],
    [4,5,6],
    [7,8,9]
]
n = int(input())
for i in list:
    for j in range(len(i)):
        i[j] = i[j] * n
print(list)

Python 解法, 执行用时: 14ms, 内存消耗: 3092KB, 提交时间: 2022-08-04

a=[[1,2,3],[4,5,6],[7,8,9]]
n= int(input())
for i in range(len(a)):
    for j in range(len(a[i])):
        a[i][j]= a[i][j]*n
print(a)
    

Python 解法, 执行用时: 15ms, 内存消耗: 2944KB, 提交时间: 2022-07-29

list1 = [1,2,3]
list2 = [4,5,6]
list3 = [7,8,9]
n = int(input())
list4 = [[x*n for x in list1], [y*n for y in list2], [z*n for z in list3]]
print(list4)