Python 解法, 执行用时: 12ms, 内存消耗: 2976KB, 提交时间: 2022-07-30

list_num = [3, 45, 9, 8, 12, 89, 103, 42, 54, 79]
x = int(input())
for item in list_num:
    if item == x:
        break
    print(item)
    

Python 解法, 执行用时: 14ms, 内存消耗: 2944KB, 提交时间: 2022-08-01

l = [3, 45, 9, 8, 12, 89, 103, 42, 54, 79]
x = int(input())
for n in l:
    if n != x:
        print(n)
    else:
        break

Python 解法, 执行用时: 14ms, 内存消耗: 2948KB, 提交时间: 2022-08-01

nums_list = [3,45,9,8,12,89,103,42,54,79]
num = int(input())
for i in nums_list:
    if int(i) == num:
        break
    print(i)
    
# l = [3, 45, 9, 8, 12, 89, 103, 42, 54, 79]
# n = int(input())
# for i in l:
#     if i-n != 0:
#         print(i)
#     else:
#         break
    

Python 解法, 执行用时: 14ms, 内存消耗: 2972KB, 提交时间: 2022-08-05

list1 = [3, 45, 9, 8, 12, 89, 103, 42, 54, 79]
x = int(input())
for i in list1:
    if i == x:
        break
    else:
        print(i)

Python 解法, 执行用时: 14ms, 内存消耗: 3028KB, 提交时间: 2022-08-04

list1 = [3, 45, 9, 8, 12, 89, 103, 42, 54, 79]
x = input()
x = int(x)
for i in list1:
    if i == x:
        break
    else:
        print(i)