Python 3 解法, 执行用时: 30ms, 内存消耗: 4580KB, 提交时间: 2022-08-05

price = {'pizza':10,'rice':2,'yogurt':5,'others':8}
str1 = input()
if str1 not in price.keys():
    str1 = 'others'
for i in price.keys():
    if i==str1:
        print(price[i])
        break

Python 3 解法, 执行用时: 31ms, 内存消耗: 4548KB, 提交时间: 2022-07-27

foods = { 'pizza':10,'rice':2 ,'yogurt':5}
food = input('')
if food in foods.keys():
    print(foods.get(food))
else:
    print(8)

Python 3 解法, 执行用时: 32ms, 内存消耗: 4472KB, 提交时间: 2022-08-01

s = input()
if s == 'pizza':
    print('10')
elif s == 'rice':
    print('2')
elif s == 'yogurt':
    print('5')
else:
    print('8')

Python 3 解法, 执行用时: 32ms, 内存消耗: 4504KB, 提交时间: 2022-07-30

food = input()
if food == 'pizza':
    print(10)
elif food == 'rice':
    print(2)
elif food == 'yogurt':
    print(5)
else:
    print(8)

Python 3 解法, 执行用时: 32ms, 内存消耗: 4512KB, 提交时间: 2022-08-06

food = input()
if food == "pizza":
    print(10)
elif food == "rice":
    print(2)
elif food == "yogurt":
    print(5)
else:
    print(8)