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上次编辑到这里,代码来自缓存 点击恢复默认模板
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* swapPairs(ListNode* head) {
}
};
运行代码
提交
python3 解法, 执行用时: 36 ms, 内存消耗: 16.1 MB, 提交时间: 2023-08-06 11:24:00
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def swapPairs(self, head: Optional[ListNode]) -> Optional[ListNode]:
if head == None or head.next == None:
return head
newHead = head.next
head.next = self.swapPairs(newHead.next)
newHead.next = head
return newHead
golang 解法, 执行用时: 0 ms, 内存消耗: 2.1 MB, 提交时间: 2021-08-10 09:57:50
/**
* Definition for singly-linked list.
* type ListNode struct {
* Val int
* Next *ListNode
* }
*/
func swapPairs(head *ListNode) *ListNode {
if head == nil || head.Next == nil {
return head
}
newHead := head.Next
head.Next = swapPairs(newHead.Next)
newHead.Next = head
return newHead
}