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/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* sortList(ListNode* head) {
}
};
python3 解法, 执行用时: 824 ms, 内存消耗: 35.1 MB, 提交时间: 2022-08-02 15:32:50
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def sortList(self, head: ListNode) -> ListNode:
def merge(head1: ListNode, head2: ListNode) -> ListNode:
dummyHead = ListNode(0)
temp, temp1, temp2 = dummyHead, head1, head2
while temp1 and temp2:
if temp1.val <= temp2.val:
temp.next = temp1
temp1 = temp1.next
else:
temp.next = temp2
temp2 = temp2.next
temp = temp.next
if temp1:
temp.next = temp1
elif temp2:
temp.next = temp2
return dummyHead.next
if not head:
return head
length = 0
node = head
while node:
length += 1
node = node.next
dummyHead = ListNode(0, head)
subLength = 1
while subLength < length:
prev, curr = dummyHead, dummyHead.next
while curr:
head1 = curr
for i in range(1, subLength):
if curr.next:
curr = curr.next
else:
break
head2 = curr.next
curr.next = None
curr = head2
for i in range(1, subLength):
if curr and curr.next:
curr = curr.next
else:
break
succ = None
if curr:
succ = curr.next
curr.next = None
merged = merge(head1, head2)
prev.next = merged
while prev.next:
prev = prev.next
curr = succ
subLength <<= 1
return dummyHead.next
python3 解法, 执行用时: 596 ms, 内存消耗: 35.2 MB, 提交时间: 2022-08-02 15:32:30
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def sortList(self, head: ListNode) -> ListNode:
def sortFunc(head: ListNode, tail: ListNode) -> ListNode:
if not head:
return head
if head.next == tail:
head.next = None
return head
slow = fast = head
while fast != tail:
slow = slow.next
fast = fast.next
if fast != tail:
fast = fast.next
mid = slow
return merge(sortFunc(head, mid), sortFunc(mid, tail))
def merge(head1: ListNode, head2: ListNode) -> ListNode:
dummyHead = ListNode(0)
temp, temp1, temp2 = dummyHead, head1, head2
while temp1 and temp2:
if temp1.val <= temp2.val:
temp.next = temp1
temp1 = temp1.next
else:
temp.next = temp2
temp2 = temp2.next
temp = temp.next
if temp1:
temp.next = temp1
elif temp2:
temp.next = temp2
return dummyHead.next
return sortFunc(head, None)
