class Solution {
public:
void reverseString(vector<char>& s) {
}
};
344. 反转字符串
编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。
不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
示例 1：
输入：s = ["h","e","l","l","o"] 输出：["o","l","l","e","h"]
示例 2：
输入：s = ["H","a","n","n","a","h"] 输出：["h","a","n","n","a","H"]
提示：
1 <= s.length <= 105s[i] 都是 ASCII 码表中的可打印字符原站题解
javascript 解法, 执行用时: 100 ms, 内存消耗: 47.9 MB, 提交时间: 2023-08-07 09:43:33
/**
* @param {character[]} s
* @return {void} Do not return anything, modify s in-place instead.
*/
var reverseString = function(s) {
const n = s.length;
for (let left = 0, right = n - 1; left < right; ++left, --right) {
[s[left], s[right]] = [s[right], s[left]];
}
};
java 解法, 执行用时: 0 ms, 内存消耗: 49.4 MB, 提交时间: 2023-08-07 09:33:42
class Solution {
public void reverseString(char[] s) {
int n = s.length;
for (int left = 0, right = n - 1; left < right; ++left, --right) {
char tmp = s[left];
s[left] = s[right];
s[right] = tmp;
}
}
}
cpp 解法, 执行用时: 20 ms, 内存消耗: 22.6 MB, 提交时间: 2023-08-07 09:30:02
class Solution {
public:
void reverseString(vector<char>& s) {
int n = s.size();
for (int left = 0, right = n - 1; left < right; ++left, --right) {
swap(s[left], s[right]);
}
}
};
golang 解法, 执行用时: 28 ms, 内存消耗: 6.3 MB, 提交时间: 2023-08-07 09:28:14
func reverseString(s []byte) {
for left, right := 0, len(s)-1; left < right; left++ {
s[left], s[right] = s[right], s[left]
right--
}
}
golang 解法, 执行用时: 32 ms, 内存消耗: 6.5 MB, 提交时间: 2021-07-15 09:32:23
func reverseString(s []byte) {
left, right := 0, len(s) - 1
for left < right {
s[left], s[right] = s[right], s[left]
left++
right--
}
}
python3 解法, 执行用时: 96 ms, 内存消耗: N/A, 提交时间: 2018-08-25 11:19:00
class Solution:
def reverseString(self, s):
"""
:type s: str
:rtype: str
"""
l = [c for c in s]
l.reverse()
return ''.join(l)