python3 解法, 执行用时: 44 ms, 内存消耗: 14.9 MB, 提交时间: 2022-11-28 14:58:38

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution:
    def partition(self, head: ListNode, x: int) -> ListNode:
        sml_dummy, big_dummy = ListNode(0), ListNode(0)
        sml, big = sml_dummy, big_dummy
        while head:
            if head.val < x:
                sml.next = head
                sml = sml.next
            else:
                big.next = head
                big = big.next
            head = head.next
        sml.next = big_dummy.next
        big.next = None
        return sml_dummy.next

javascript 解法, 执行用时: 88 ms, 内存消耗: 42.6 MB, 提交时间: 2022-11-27 13:21:41

/**
 * Definition for singly-linked list.
 * function ListNode(val) {
 *     this.val = val;
 *     this.next = null;
 * }
 */
/**
 * @param {ListNode} head
 * @param {number} x
 * @return {ListNode}
 */
var partition = function(head, x) {
    let small = new ListNode(0);
    const smallHead = small;
    let large = new ListNode(0);
    const largeHead = large;
    while (head !== null) {
        if (head.val < x) {
            small.next = head;
            small = small.next;
        } else {
            large.next = head;
            large = large.next;
        }
        head = head.next;
    }
    large.next = null;
    small.next = largeHead.next;
    return smallHead.next;
};

golang 解法, 执行用时: 4 ms, 内存消耗: 2.3 MB, 提交时间: 2022-11-27 13:21:22

/**
 * Definition for singly-linked list.
 * type ListNode struct {
 *     Val int
 *     Next *ListNode
 * }
 */
func partition(head *ListNode, x int) *ListNode {
    small := &ListNode{}
    smallHead := small
    large := &ListNode{}
    largeHead := large
    for head != nil {
        if head.Val < x {
            small.Next = head
            small = small.Next
        } else {
            large.Next = head
            large = large.Next
        }
        head = head.Next
    }
    large.Next = nil
    small.Next = largeHead.Next
    return smallHead.Next
}