class Solution {
public:
int numberOfDays(int year, int month) {
}
};
1118. 一月有多少天
指定年份 year 和月份 month，返回 该月天数 。
示例 1：
输入：year = 1992, month = 7 输出：31
示例 2：
输入：year = 2000, month = 2 输出：29
示例 3：
输入：year = 1900, month = 2 输出：28
提示：
1583 <= year <= 21001 <= month <= 12原站题解
java 解法, 执行用时: 0 ms, 内存消耗: 38 MB, 提交时间: 2023-10-15 15:31:56
class Solution {
public int numberOfDays(int Y, int M) {
int[] year1 = {31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; // 闰年
int[] year2 = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; // 非闰年
if((Y % 100 != 0 && Y % 4 == 0) || Y % 400 == 0) {
return year1[M-1];
}
return year2[M-1];
}
}
cpp 解法, 执行用时: 0 ms, 内存消耗: 6.4 MB, 提交时间: 2023-10-15 15:31:45
class Solution {
public:
int numberOfDays(int Y, int M) {
int year[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
if (M == 2 && Y % 4 == 0 && (Y % 100 != 0 || Y % 400 == 0)) // 闰二月
return 29;
else
return year[M - 1];
}
};
golang 解法, 执行用时: 4 ms, 内存消耗: 1.8 MB, 提交时间: 2023-10-15 15:31:33
func numberOfDays(Y int, M int) int {
// 把时间先加到下个月的第一天，再减掉一天就是本月的最后一天了
return time.Date(Y, time.Month(M+1), 1, 0, 0, 0, 0, time.Local).AddDate(0, 0, -1).Day()
}
func numberOfDays2(Y int, M int) int {
year1 := []int{31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31} // 闰年
year2 := []int{31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31} // 非闰年
if (Y % 100 != 0 && Y % 4 == 0) || Y % 400 == 0 {
return year1[M-1];
}
return year2[M-1];
}
python3 解法, 执行用时: 40 ms, 内存消耗: 16 MB, 提交时间: 2023-10-15 15:31:12
class Solution:
def numberOfDays(self, Y: int, M: int) -> int:
if (Y % 100 != 0 and Y % 4 == 0) or Y % 400 == 0:
return [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31][M - 1] # 闰年
else:
return [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31][M - 1] # 非闰年