# Write your MySQL query statement below
620. 有趣的电影
某城市开了一家新的电影院，吸引了很多人过来看电影。该电影院特别注意用户体验，专门有个 LED显示板做电影推荐，上面公布着影评和相关电影描述。
作为该电影院的信息部主管，您需要编写一个 SQL查询，找出所有影片描述为非 boring (不无聊) 的并且 id 为奇数 的影片，结果请按等级 rating 排列。
例如，下表 cinema:
+---------+-----------+--------------+-----------+ | id | movie | description | rating | +---------+-----------+--------------+-----------+ | 1 | War | great 3D | 8.9 | | 2 | Science | fiction | 8.5 | | 3 | irish | boring | 6.2 | | 4 | Ice song | Fantacy | 8.6 | | 5 | House card| Interesting| 9.1 | +---------+-----------+--------------+-----------+
对于上面的例子，则正确的输出是为：
+---------+-----------+--------------+-----------+ | id | movie | description | rating | +---------+-----------+--------------+-----------+ | 5 | House card| Interesting| 9.1 | | 1 | War | great 3D | 8.9 | +---------+-----------+--------------+-----------+
原站题解
pythondata 解法, 执行用时: 248 ms, 内存消耗: 59.1 MB, 提交时间: 2023-09-17 10:45:08
import pandas as pd
def not_boring_movies(cinema: pd.DataFrame) -> pd.DataFrame:
return cinema[(cinema['description']!='boring') & (cinema['id']%2==1)].sort_values(by='rating',ascending=False)
mysql 解法, 执行用时: 238 ms, 内存消耗: N/A, 提交时间: 2018-08-22 00:03:54
# Write your MySQL query statement below select * from cinema where id%2=1 and description<>'boring' order by rating desc;