# Write your MySQL query statement below
1205. 每月交易 II
Transactions
记录表
+----------------+---------+ | Column Name | Type | +----------------+---------+ | id | int | | country | varchar | | state | enum | | amount | int | | trans_date | date | +----------------+---------+ id 是这个表的主键。 该表包含有关传入事务的信息。 状态列是枚举类型,值为 [approved、declined] 其中之一的列。
Chargebacks
表
+----------------+---------+ | Column Name | Type | +----------------+---------+ | trans_id | int | | trans_date | date | +----------------+---------+ 退单包含有关放置在事务表中的某些事务的传入退单的基本信息。 trans_id 是 transactions 表的 id 列的外键(reference 列)。 每项退单都对应于之前进行的交易,即使未经批准。
编写一个解决方案,找出每个国家/地区的每月交易信息:已批准交易的数量及其总金额、退单的数量及其总金额。
注意:在你的解决方案中,只需显示给定月份和国家,忽略所有为零的行。
以 任意顺序 返回结果表。
结果格式如下所示。
示例 1:
输入: Transactions 表: +-----+---------+----------+--------+------------+ | id | country | state | amount | trans_date | +-----+---------+----------+--------+------------+ | 101 | US | approved | 1000 | 2019-05-18 | | 102 | US | declined | 2000 | 2019-05-19 | | 103 | US | approved | 3000 | 2019-06-10 | | 104 | US | declined | 4000 | 2019-06-13 | | 105 | US | approved | 5000 | 2019-06-15 | +-----+---------+----------+--------+------------+ Chargebacks 表: +----------+------------+ | trans_id | trans_date | +----------+------------+ | 102 | 2019-05-29 | | 101 | 2019-06-30 | | 105 | 2019-09-18 | +----------+------------+ 输出: +---------+---------+----------------+-----------------+------------------+-------------------+ | month | country | approved_count | approved_amount | chargeback_count | chargeback_amount | +---------+---------+----------------+-----------------+------------------+-------------------+ | 2019-05 | US | 1 | 1000 | 1 | 2000 | | 2019-06 | US | 2 | 8000 | 1 | 1000 | | 2019-09 | US | 0 | 0 | 1 | 5000 | +---------+---------+----------------+-----------------+------------------+-------------------+
原站题解
mysql 解法, 执行用时: 513 ms, 内存消耗: 0 B, 提交时间: 2023-10-16 14:24:11
# Write your MySQL query statement below SELECT month, country, COUNT(IF(tag=1, 1, NULL)) AS approved_count, SUM(IF(tag=1, amount, 0)) AS approved_amount, COUNT(IF(tag=0, 1, NULL)) AS chargeback_count, SUM(IF(tag=0, amount, 0)) AS chargeback_amount FROM ( SELECT country, amount, 1 AS tag, date_format(trans_date, '%Y-%m') AS month FROM Transactions WHERE state='approved' UNION ALL SELECT country, amount, 0 AS tag, date_format(c.trans_date, '%Y-%m') AS month FROM Transactions AS t RIGHT OUTER JOIN Chargebacks AS c ON t.id = c.trans_id ) AS temp GROUP BY month, country;