class Solution {
public:
vector<string> fizzBuzz(int n) {
}
};
412. Fizz Buzz
给你一个整数 n ，找出从 1 到 n 各个整数的 Fizz Buzz 表示，并用字符串数组 answer（下标从 1 开始）返回结果，其中：
answer[i] == "FizzBuzz" 如果 i 同时是 3 和 5 的倍数。answer[i] == "Fizz" 如果 i 是 3 的倍数。answer[i] == "Buzz" 如果 i 是 5 的倍数。answer[i] == i （以字符串形式）如果上述条件全不满足。
示例 1：
输入：n = 3 输出：["1","2","Fizz"]
示例 2：
输入：n = 5 输出：["1","2","Fizz","4","Buzz"]
示例 3：
输入：n = 15 输出：["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]
提示：
1 <= n <= 104原站题解
golang 解法, 执行用时: 4 ms, 内存消耗: 3.4 MB, 提交时间: 2021-06-15 15:05:28
func fizzBuzz(n int) []string {
ans := make([]string, n+1)
for i := 1; i <= n; i++ {
if i % 15 == 0 {
ans[i] = "FizzBuzz"
} else if i % 3 == 0 {
ans[i] = "Fizz"
} else if i % 5 == 0 {
ans[i] = "Buzz"
} else {
ans[i] = strconv.Itoa(i)
}
}
return ans[1:]
}