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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
int findBottomLeftValue(TreeNode* root) {
}
};
golang 解法, 执行用时: 4 ms, 内存消耗: 5.1 MB, 提交时间: 2022-11-11 13:56:01
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
func findBottomLeftValue(root *TreeNode) (ans int) {
q := []*TreeNode{root}
for len(q) > 0 {
node := q[0]
q = q[1:]
if node.Right != nil {
q = append(q, node.Right)
}
if node.Left != nil {
q = append(q, node.Left)
}
ans = node.Val
}
return
}
