class Solution {
public:
bool detectCapitalUse(string word) {
}
};
520. 检测大写字母
我们定义，在以下情况时，单词的大写用法是正确的：
"USA" 。"leetcode" 。"Google" 。给你一个字符串 word 。如果大写用法正确，返回 true ；否则，返回 false 。
示例 1：
输入：word = "USA" 输出：true
示例 2：
输入：word = "FlaG" 输出：false
提示：
1 <= word.length <= 100word 由小写和大写英文字母组成原站题解
python3 解法, 执行用时: 35 ms, 内存消耗: 16.4 MB, 提交时间: 2024-06-23 10:57:16
class Solution:
def detectCapitalUse(self, word: str) -> bool:
return word.islower() or word.isupper() or word.istitle()
def detectCapitalUse2(self, word: str) -> bool:
cnt = sum(c.isupper() for c in word)
return cnt == 0 or cnt == len(word) or cnt == 1 and word[0].isupper()
java 解法, 执行用时: 1 ms, 内存消耗: 41.1 MB, 提交时间: 2024-06-23 10:56:46
public class Solution {
public boolean detectCapitalUse(String word) {
int cnt = 0;
for (char c : word.toCharArray()) {
if (Character.isUpperCase(c)) {
cnt++;
}
}
return cnt == 0 || cnt == word.length() || cnt == 1 && Character.isUpperCase(word.charAt(0));
}
}
rust 解法, 执行用时: 0 ms, 内存消耗: 2.1 MB, 提交时间: 2024-06-23 10:56:24
impl Solution {
pub fn detect_capital_use(word: String) -> bool {
let cnt = word.chars().filter(|&c| c.is_uppercase()).count();
cnt == 0 || cnt == word.len() || cnt == 1 && word.chars().next().unwrap().is_uppercase()
}
}
javascript 解法, 执行用时: 65 ms, 内存消耗: 49.8 MB, 提交时间: 2024-06-23 10:56:09
/**
* @param {string} word
* @return {boolean}
*/
var detectCapitalUse = function(word) {
const cnt = _.sumBy(word, c => c === c.toUpperCase() ? 1 : 0);
return cnt === 0 || cnt === word.length || cnt === 1 && word[0] === word[0].toUpperCase();
};
cpp 解法, 执行用时: 0 ms, 内存消耗: 7.4 MB, 提交时间: 2024-06-23 10:55:41
class Solution {
public:
bool detectCapitalUse(string word) {
int cnt = ranges::count_if(word, [](char c) { return isupper(c); });
return cnt == 0 || cnt == word.length() || cnt == 1 && isupper(word[0]);
}
};
golang 解法, 执行用时: 0 ms, 内存消耗: 2 MB, 提交时间: 2021-06-23 18:32:17
func detectCapitalUse(word string) bool {
if unicode.IsUpper(rune(word[0])) {
return strings.ToUpper(word[1:]) == word[1:] || strings.ToLower(word[1:]) == word[1:]
}
return strings.ToLower(word) == word
}