# Write your MySQL query statement below
1355. 活动参与者
表: Friends
+---------------+---------+ | Column Name | Type | +---------------+---------+ | id | int | | name | varchar | | activity | varchar | +---------------+---------+ id 是朋友的 id,并且在 SQL 中,是该表的主键 name 是朋友的名字 activity 是朋友参加的活动的名字
表: Activities
+---------------+---------+ | Column Name | Type | +---------------+---------+ | id | int | | name | varchar | +---------------+---------+ 在 SQL 中,id 是该表的主键 name 是活动的名字
找出那些既没有最多,也没有最少参与者的活动的名字。
Activities
表中的任意活动都有在 Friends
中参与过。
可以以 任何顺序 返回结果。
下面是返回结果格式的例子。
示例 1:
输入: Friends 表: +------+--------------+---------------+ | id | name | activity | +------+--------------+---------------+ | 1 | Jonathan D. | Eating | | 2 | Jade W. | Singing | | 3 | Victor J. | Singing | | 4 | Elvis Q. | Eating | | 5 | Daniel A. | Eating | | 6 | Bob B. | Horse Riding | +------+--------------+---------------+ Activities 表: +------+--------------+ | id | name | +------+--------------+ | 1 | Eating | | 2 | Singing | | 3 | Horse Riding | +------+--------------+ 输出: +--------------+ | activity | +--------------+ | Singing | +--------------+ 解释: Eating 活动有三个人参加, 是最多人参加的活动 (Jonathan D. , Elvis Q. and Daniel A.) Horse Riding 活动有一个人参加, 是最少人参加的活动 (Bob B.) Singing 活动有两个人参加 (Victor J. and Jade W.)
原站题解
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# Write your MySQL query statement below select activity as ACTIVITY from friends group by activity having count(*)>any( select count(*) from friends group by activity ) and count(*)<any( select count(*) from friends group by activity )