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XOR with fixed length key

Welcome   CTF-2023   Crypto  

题目作者: 未知

一  血: ‌‌‌‌‌暂无

一血奖励: 0金币

解  决: 0

提  示:

import os, random, hashlib  from itertools import cycle    pt   = [i%230 for i in os.urandom(500000)]  klen = random.randint(1000,10000)  key  = random.getrandbits(klen*8).to_bytes(klen, 'big')    open('ct', 'wb').write(bytes(c^i for c,i in zip(pt, cycle(key))))    flag = "greyhats{%s}"%hashlib.sha256(key).hexdigest()  print(flag)  

JuliaPoo Hint: Gotten the key length but there's too many possibilities? That's great! Now you can ignore the non-uniform distribution of the plaintext and focus entirely on exploiting python's random module.

Mini technicality: Please assume that klen and key are generated independently. This is because the challenge file was generated 2 years ago and I can no longer guarantee that they are generated with the same random internal state given that I have the memory of a goldfish. Regardless, the intended solution doesn't require klen to be generated with the same random internal state.

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